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Kazeer [188]
3 years ago
11

A Type I muscle fibers have an average diameter of 98 µm, and can exert a compressive load of 532 µN[1]. If they are modeled as

a perfect cylinder, what is the stress in an individual fiber?
Engineering
1 answer:
Kitty [74]3 years ago
6 0

Answer:

stress is 70529.30 N/m²

Explanation:

given data

diameter = 98 µm = 98 × 10^{-6} m

compressive load = 532 µN = 532 × 10^{-6} N

to find out

stress in an individual fiber

solution

we know that stress formula that is

stress = \frac{load}{area}     ................1

put here value we get  stress

stress = \frac{load}{area}

stress = \frac{532*10^{-6}}{\frac{\pi }{4} (98*10^{-6})^2}

stress = 70529.30 N/m²

so stress is 70529.30 N/m²

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determine the optimum compressor pressure ratio specific thrust fuel comsumption 2.1 220k 1700k 42000 1.004
Afina-wow [57]

Answer:

hello your question is incomplete attached below is the complete question

A) optimum compressor ratio = 9.144

B) specific thrust = 2.155 N.s /kg

C) Thrust specific fuel consumption = 1670.4 kg/N.h

Explanation:

Given data :

Mo = 2.1 ,  To = 220k , Tt4 = 1700 k, hpr = 42000 kj/kg, Cp = 1.004 kj/ kg.k

γ = 1.4

attached below is the detailed solution

6 0
3 years ago
Assign numMatches with the number of elements in userValues that equal matchValue. userValues has NUM_VALS elements. Ex: If user
erica [24]

Answer:

import java.util.Scanner;

public class FindMatchValue {

  public static void main (String [] args) {

     Scanner scnr = new Scanner(System.in);

     final int NUM_VALS = 4;

     int[] userValues = new int[NUM_VALS];

     int i;

     int matchValue;

     int numMatches = -99; // Assign numMatches with 0 before your for loop

     matchValue = scnr.nextInt();

     for (i = 0; i < userValues.length; ++i) {

        userValues[i] = scnr.nextInt();

     }

     /* Your solution goes here */

         numMatches = 0;

     for (i = 0; i < userValues.length; ++i) {

        if(userValues[i] == matchValue) {

                       numMatches++;

                }

     }

     System.out.println("matchValue: " + matchValue + ", numMatches: " + numMatches);

  }

}

6 0
3 years ago
Using what you know about the NAND gate, draw how you could implement a three-input NAND gate using NMOS and PMOS transistors. T
Yuliya22 [10]

Answer:

use this, it should help you understand

Explanation:

https://www.electronics-tutorials.ws/logic/logic_5.html

4 0
3 years ago
Christopher has designed a fluid power system that repeatedly gets clogs. Which of the following objects should he choose to add
MA_775_DIABLO [31]

Answer:

Valve

Explanation:

Its right

3 0
3 years ago
Write a do-while loop that continues to prompt a user to enter a number less than 100, until the entered number is actually less
chubhunter [2.5K]

Answer:

#include <iostream>//including iostream library to use functions such as cout and cin

using namespace std;

int main() {

int userInput = 0;

do

{

 cout << "Enter a number < 100: " ;

 cin >> userInput;

 if (userInput < 100)//condition if number is less than 100

 {

  cout << "Your number < 100 is: " << userInput << endl;

 }

} while (userInput > 100);//do while loop condition

return 0;

}

Explanation:

A do-while loop executes regardless in the first iteration. Once it has run through the first iteration, it checks if the condition is being met. If, the condition is TRUE, the loop begins the second iteration. If FALSE, the loop exits. In this case, the condition is the userInput. after the first iteration, lets say the userInput is 120, the condition userInput > 100 is true.Therefore, the loop will run again until eventually the number is less than hundred, lets say 25. In that case the condition would be 25 > 100, which would be false, so the loops will break.

8 0
4 years ago
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