Question

As a new electrical technician, you are designing a large solenoid to produce a uniform 0.150-T magnetic field near the center of the solenoid. You have enough wire for 3100 circular turns. This solenoid must be 57.0 cm long and 7.00 cm in diameter.What current will you need to produce the necessary field?

Answer 1

Answer:

I = 21.94 A

Explanation:

Given that

B= 0.15 T

Number of turns N= 3100

Length L = 57 cm

Diameter ,d= 7 cm

We know that magnetic field in the solenoid given as

$B=\dfrac{\mu_0IN}{L}$

$I=\dfrac{BL}{\mu_0N}$

Now by putting the values

$I=\dfrac{0.15\times 0.57}{4\pi \times 10^{-7}\times 3100}$

I = 21.94 A

Therefore current need to produce 0.15 T magnetic filed is 21.94 A.