J, K, and L are collinear
J is between K and L
LK = KJ + LJ
LK = 9x + 7
KJ = 2x - 3
LJ = 4x - 8
9x + 7 = (2x - 3) + (4x - 8)
9x + 7 = (2x + 4x) + (-3 - 8)
9x + 7 = 6x + -11
9x + 7 = 6x - 11
9x + 7 - 7 = 6x - 11 - 7
9x = 6x - 18
9x - 6x = 6x - 6x - 18
3x = -18
x = -6
∴ The value of x is -6
Answer:5x
Step-by-step explanation:
Answer:
All Calendula College students enrolled in the spring.
Step-by-step explanation:
A researcher at Calendula College wishes to estimate the number of units earned by students during the spring semester at Calendula.
To do so, he randomly selects 100 student transcripts from among all Calendula College students enrolled in the spring and records the number of units each student earned in the spring term.
It would stop at 3y+4>11 because the 3y and 4 are unlike terms and can only be divided or multiplied.
