All categories

3 years ago

What is the product of the binomials below?

Mathematics

1 answer:

fgiga [73]3 years ago

3 0

Answer:

$\boxed{ \bold{ \huge{ \boxed{ \sf{6 {x}^{2} + 23x + 20}}}}}$

Option A is the correct option.

Step-by-step explanation:

$\sf{(2x + 5)(3x + 4)}$

Use the distributive property to multiply each term of the first binomial by each term of the second binomial

⇒ $\sf{2x(3x + 4) + 5(3x + 4)}$

⇒ $\sf{6 {x}^{2} + 8x + 15x + 20}$

Collect like terms

⇒ $\sf{6 {x}^{2} + 23x + 20}$

Hope I helped !

Best regards!!

You might be interested in

HEEELLLLPPP!!!! PLZZZZ!!!! THANK U!!!<br> (5 screenshots included)

IRISSAK [1]

1.=(2/3,0) 2.=(-3,0) 3.=-10 4.=need a graphing calc 5.=need a graphing calc

6 0

2 years ago

Noel has rowing lessons every 5 days and guitar lessons every 6 days. If he had both lessons on the last day of the previous mon

bixtya [17]

Answer:

Since every 30 days he wil have both lessons on the same day , and he already had both lessons on the last day of the previous month, that means that the day 30 the current month he wil have both lessons on the same day (It may be the last day if the month has 30 days or it may not be the last day if the month has 31 days)

Step-by-step explanation:

Lets find the least common factor of 5 and 6

Multiples of 5

5 10 15 20 35 30 35 40......

Multiples of 6

6 12 18 24 30 36

LCF of 5 and 6 = 30

Every 30 days he wil have both lessons on the same day

3 0

3 years ago

What is the probability that 2 randomly selected months have 31 days?

aniked [119]

Answer:

31.8%

Step-by-step explanation:There are 7 months that have 31 days so,

The odds the first selected month has 31 days is 7/12

The next month there are only 6 months left with 31 days of only 11 months to choose from

so the odds for the second are 6/11

To calculate the odds they BOTH have 31 months you multiply the two odds:

(7/12) x (6/11) = 42/132 = .318 so 31.8%

6 0

2 years ago

Read 2 more answers

X + one over two(6x − 4) = 6

Maurinko [17]

The given equation is:

x+ $\frac{1}{2} (6x-4)=6.$

Multiplying both sides by 2 we have:

2x + 6x − 4 = 12 [ multiplication property of equality]

Combining like terms:

8x-4=12

Adding 4 both sides

8x=16.[Addition property of equality]

Dividing both sides by 8:

x=2 [Division property of equality.]

The correct option in which the equation is solved are : B. Multiplication property of equality. 2. Combine like terms. 3. Addition property of equality. 4. Division property of equality.

7 0

2 years ago

At the movies, a couple bought 2 medium drinks and a large popcorn for $13.85. At the same theater, a family bought 3 medium dri

m_a_m_a [10]

Answer:

a) the cost of one medium drink be $3.80

b) the cost of a large popcorn be $6.25

Step-by-step explanation:

Let the cost of one medium drink be $x

and the cost of a large popcorn be $y

According to question,

A couple bought 2 medium drinks and a large popcorn for $13.85.

2x + y = 13.85 ..............(1)

A family bought 3 medium drinks and 2 large popcorn for a total of $23.90

3x + 2y = 23.90 ..............(2)

Using Elimination method to solve the system of equation,

Multiply equation (1) by 2 , we get,

4x + 2y = 27.70 ..............(3)

Now, subtract equation (2) from (3), we get,

4x + 2y-(3x + 2y) = 27.70 - 23.90

4x + 2y-3x - 2y = 3.80

4x -3x = 3.80

x = 3.80

Substitute, x = 3.8 in (1) ,

2(3.80) + y = 13.85

7.60 +y = 13.85

y = 6.25

Therefore, the cost of one medium drink be $3.80

and the cost of a large popcorn be $6.25

7 0

3 years ago

Read 2 more answers