In order to determine this, we will first need some conversions. We will need to convert metric tons and grams into one another and also cubic centimeters to cubic meters into one another.
1 metric ton = 1000 kg
1 kg = 1000 grams
1 metric ton = 10⁶ grams
So 10⁶ grams / metric ton
1 meter = 100 cm
1 m³ = (100)³ cm³
1 m³ = 10⁶ cm³
So 10⁶ cm⁶ / m³
Now, we manipulate the given value:
(19.3 grams / cm³) * (1 metric ton / 10⁶ grams) * (10⁶ cm³ / m³)
= 19.3 metric tons / m³
The density of gold is 19.3 metric tons meter meter cubed.
Answer:
1840:1
Explanation:
If m is the mass of the electron, and 1840m is the mass of the proton, then:
p₁ = p₂
m₁v₁ = m₂v₂
m v₁ = 1840m v₂
v₁ = 1840 v₂
The kinetic energy of the electron is:
KE₁ = ½ m₁ v₁²
KE₁ = ½ m (1840 v)²
KE₁ = 1692800 mv²
The kinetic energy of the proton is:
KE₂ = ½ m₂ v₂²
KE₂ = ½ (1840m) v₂²
KE₂ = 920 mv²
The ratio of the kinetic energies is:
KE₁ / KE₂
(1692800 mv²) / (920 mv²)
1840:1
Answer:
470 N.
Explanation:
Using equations of motion:
S = vi*t + 1/2*(a*(t^2))
Given:
S = 0.65 m
t = 1.5 s
vi = 0 m/s
0.65 = 1/2 * (a * (1.5)^2)
a = 1.3/2.25
= 0.578 m/s^2
Force = mass * acceleration due to gravity
= 92 * 0.578
= 53.16 N
Total force = 420 + 53.16
= 473.16 N
= 470 N.
c) To determine the velocity of the motion at the given time, consider that the velocity is also the area under the line of the graph a vs t.
Between t=0s and t = 2 s, the area under the line is:
A1 = 2 X 2 = 4
Then, until t = 2s the velocity is 4 m/s
The area between t = 2s and t = 4 s is:
A2 = 2 x 0 = 0
The area between t = 4s and t = 5s, the area is:
A3 = 2 x 1 = 2
Now, consider that the velocity is the sum of the previous areas, but taking areas on the negative y-axis as negative ones. Then, you have:
A = A1 + A2 - A3 = 4 + 0 - 2 = 2
Hence, the velocity is 2 m/s
The bigger the slower it will decreases in heat and smaller the faster it will be