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dlinn [17]
2 years ago
15

Question 3 of 32

Physics
1 answer:
Scorpion4ik [409]2 years ago
3 0

Answer:

the clown can be put on a sealion and the other clown can hold a lot of peole  he help a clown that was tall and heivy

Explanation:

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Two thermometers are calibrated, one in de
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-40 c = -40 f but k would be 233.15
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A 10 N force is used to push a 30 kg box across the floor, moving it a distance of 20 m. There is no friction. What is the magni
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Work=Force • Distance
W= 10N • 20m
W= 200 J

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Calculate the acceleration of an airplane that starts at rest and reaches a speed 45m/s in 9 seconds
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I believe the acceleration would be 5m/s

All you would need to do is divide the final speed by the time it took to get there. I am only about 80 sure this answer is correct, so take my advise only if you feel comfortable.

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Magnetic fields are an area around a magnetic material or a moving electric charge with which the force of magnet
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A block is attached to a horizontal spring and oscillates back and forth on a frictionless horizontal surface at a frequency of
Nastasia [14]

Answer:

Amplitude = 0.058m

Frequency = 6.25Hz

Explanation:

Given

Amplitude (A) = 8.26 x 10-2 m

Frequency (f) = 4.42Hz

Conversation of energy before split

½mv² = ½KA²

Make A the subject of formula

A = v\sqrt{\frac{m}{k} }

Conversation of energy after split

½(m/2)V'² = ½(m/2)V² = ½KA'²

½(m/2)V² = ½KA'²

Make A the subject of formula

First divide both sides by ½

(m/2)V² = KA'²

Divide both sides by K

\frac{m}{2K}V² = A'²

v\sqrt{\frac{m}{2k} } = A'

Substitute v\sqrt{\frac{m}{k} } for A in the above equation

A' = A/√2

A' = 8.26 x 10^-2/√2

A' = 0.05840702012600882

Amplitude after split = 0.058 (Approximated)

Frequency (f') = f√2

f' = 4.42√2

f' = 6.25082394568908011

Frequency after split = 6.25Hz (approximated)

8 0
3 years ago
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