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dlinn [17]
2 years ago
15

Question 3 of 32

Physics
1 answer:
Scorpion4ik [409]2 years ago
3 0

Answer:

the clown can be put on a sealion and the other clown can hold a lot of peole  he help a clown that was tall and heivy

Explanation:

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When 560,000 is written in scientific notation, what is the power of 10?
tensa zangetsu [6.8K]
5.6•10^5 so it’s to the power of positive 5
3 0
3 years ago
Read 2 more answers
A solid steel column is 4.0 m long and 0.20 m in diameter. Young's modulus for this steel is 2.0 × 1011 N/m2. By what distance d
zzz [600]

Answer:

3.12 x 10^-5 m

Explanation:

Length of steel column, L = 4 m

diameter, d = 0.2 m

radius = half of diameter = 0.1 m

Young's modulus, Y = 2 x 10^11 N/m^2

Mass of truck, m = 5000 kg

Force, F = mass of truck x acceleration due to gravity

F = 5000 x 9.8 = 49000 N

Area of crossection of cable,

A =  \pi r^{2}=3.14\times\0.1\times0.1=0.0314m^{2}

Let ΔL be the shrink in length of cable, then by the formula of Young's modulus

Y=\frac{F\times L}{A\times\Delta L}

\Delta L = \frac{F\times L}{A\times Y}

\Delta L = \frac{49000\times 4}{0.0314\times 2\times10^{11}}

ΔL = 3.12 x 10^-5 m

Thus, the shrink in the length of cable is 3.12 x 10^-5 m.

8 0
3 years ago
A bus and a car have an inelastic head-on collision. The bus has a mass of 1.5 × 103 kilograms and an initial velocity of 20 met
makkiz [27]

Answer:

+5300 kg m/s

Explanation:

In any type of collision, the total momentum is conserved. Therefore, we can just calculate the total momentum before the collision, and the final momentum will be equal to the initial one.

The total momentum before the collision is:

p_i = m_1 u_1 + m_2 u_2

where

m_1 = 1.5 \cdot 10^3 kg is the mass of the bus

m_2 = 9.5\cdot 10^2 kg is the mass of the car

u_1 = 20 m/s is the initial velocity of the bus

u_2 = -26 m/s is the initial velocity of the car

Substituting the numbers, we find

p_1 = (1.5 \cdot 10^3 kg)(20 m/s)+(9.5\cdot 10^2 kg)(-26 m/s)=5300 kg m/s

And since the total momentum is conserved, this is also the final momentum after the collision.

7 0
3 years ago
Read 2 more answers
Two identical conducting spheres each having a radius of 0.500 cm are connected by a light, 1.90-m-long conducting wire. A charg
Ivan

Answer: 4.19 N

Explanation: In order to determinate the tension applied on the wire we have to calculate the electric force between the conductor spheres connected by the wire.

As the wire is a conductor the spheres are at same potential so we have:

V1=V2

V1=k*Q1/r1 and V2=k*Q2/r2

where r1=r2, then

Q1=Q2

so the electric force is given by:

F=k*Q^2/d^2  where d is the distance between the spheres.

Finally replacing the values,  we have

F=9*10^9(41*10^-6)^2/(1.9)^2= 4.19 N

8 0
3 years ago
I mark brainliest!!!!
densk [106]

Answer:

I think it is False.

Explanation:

I think that a body could not be vertical for every time.

6 0
3 years ago
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