Answer:
563.86 N
Explanation:
We know the buoyant force F = weight of air displaced by the balloon.
F = ρgV where ρ = density of air = 1.29 kg/m³, g = acceleration due to gravity = 9.8 m/s² and V = volume of balloon = 4πr/3 (since it is a sphere) where r = radius of balloon = 2.20 m
So, F = ρgV = ρg4πr³/3
substituting the values of the variables into the equation, we have
F = 1.29 kg/m³ × 9.8 m/s² × 4π × (2.20 m)³/3
= 1691.58 N/3
= 563.86 N
Answer:
Final mass=0.89kg
Final pressure=5.6bar
Explanation:
To find mass,m=v/v1
But v1=vf + x(vg-vf)
Vf= 0.001093m^3/kg
Vg= 0.3748m^3/kg
V1= 0.001093+0.5(0.3748-0.001093)
V1= 0.225m^3/kg
M= 0.20/0.225 =0.89kg
Final pressure will be:
V/V1= P/P1
Cross multiply
VP1=V1P
P1= 0.225×5/0.2
P1=:5.6 bar
Answer:
B = 8.0487mT
Explanation:
To solve the exercise it is necessary to take into account the considerations of the Magnetic Force described by Faraday,
The magnetic force is given by the formula

Where,
B = Magnetic Field
I = Current
L = Length
Angle between the magnetic field and the velocity, for this case are perpendicular, then is 90 degrees
According to our data we have that
I = 16.4A
F = 0.132N/m
As we know our equation must be modificated to Force per length unit, that is

Replacing the values we have that

Solving for B,


Yes basic, calculus, and trig
<u><em>In accordance with the International Regulation for the prevention of collisions at sea</em></u><u>:
</u>
<u>1.- A sailing boat has a passing preference over a motorized boat, </u><u>except when the motor boat is limited by its draft</u><u>.
</u>
<u>2.- The sailboat must maintain its course and speed.
</u>
<u>3.- </u><em><u>If it is evident that the PWC does not respond</u></em><u>, the sailboat must sound the warning signal, and change its course to starboard.
</u>
<u>4.- </u><u><em>All actions must be taken as soon as possible</em></u><u>.
</u>
<u>5.- If a sailboat is using its engine, the situation changes, and in that case, both ships must alter to starboard.</u>