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Elanso [62]
3 years ago
6

Countercurrent exchange is evident in the flow of _____.

Physics
1 answer:
Anna35 [415]3 years ago
4 0

Answer:

In the water flow mechanism in fishes when they take in oxygen using the gills

Explanation:

Fish gills are organ that facilites respiration under water,its Mechanism is described below,first water is pulled in the mouth of the fish and pumped over the gills,while the blood flow in opposite direction known as counter current exchange helps in pushing low oxgen water away and retaining high oxgen in the fish blood.

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Normal atmospheric pressure at sea level is ?
iris [78.8K]
1 bar or 100 000 pascales. Or 1020 hPa. It kinda differentiates.
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The complete combustion of a small wooden match produces approximately 512 cal of heat. How many kilojoules are produced? Expres
k0ka [10]

We have to covert 512 cal of heat in kilo joules.

As, 1 cal = 0.004184 kJ = 4.184 joules.

Therefore,

512 \ cal = 512 \times 4.184 \ J = 2142.208 \ J \\\\\ =  2.142 \times 10 ^3 J = 2.142 \ kJ

Thus, combustion of a small wooden match produces approximately ( in kilo joules ) is 2.142 kJ .

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3 years ago
What do scientists do to easily share measurement data they can understand?
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3 0
4 years ago
Read 2 more answers
What is the magnitude of the torque about his shoulder if he holds his arm straight out to his side, parallel to the floor
const2013 [10]

Complete Question

An athlete at the gym holds a 3.0 kg steel ball in his hand. His arm is 70 cm long and has a mass of 4.0 kg. Assume, a bit unrealistically, that the athlete's arm is uniform.

What is the magnitude of the torque about his shoulder if he holds his arm straight out to his side, parallel to the floor? Include the torque due to the steel ball, as well as the torque due to the arm's weight.

Answer:

The torque is  \tau = 34.3 \  N\cdot m

Explanation:

From the question we are told that

   The mass of the steel ball is  m  =  3.0 \  kg

    The length of arm is  l =  70 \ cm  = 0.7 \  m

    The mass of the arm is m_a  = 4.0 \  kg

Given that the arm of the athlete is uniform them the distance from the shoulder to the center of gravity of the arm is mathematically represented as

       r = \frac{l}{2}

=>    r = \frac{ 0.7}{2}  

=>    r = 0.35 \ m  

Generally the magnitude of torque about the athlete shoulder is mathematically represented as

      \tau =  m_a * g * r  + m * g *  L

=>    \tau =  4 * 9.8 * 0.35 + 3 * 9.8 *  0.70

=>    \tau = 34.3 \  N\cdot m

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3 years ago
Which image shows an example of the strong nuclear force in action?
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i think this is the incomplete page that you are showing but the answer is

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<h2><u>B</u></h2>
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