As we know that mass of the box is given as
m = 9.5 kg
acceleration of the box is given as
so by Newton's II law we can say
now we can substitute all the values in it
So it required 9.5 N force to slide it
Complete Question:
Gauss's law:
Group of answer choices
A. can always be used to calculate the electric field.
B. relates the electric field throughout space to the charges distributed through that space.
C. only applies to point charges.
D. relates the electric field at points on a closed surface to the net charge enclosed by that surface.
E. relates the surface charge density to the electric field.
Answer:
D. relates the electric field at points on a closed surface to the net charge enclosed by that surface.
Explanation:
Gauss's law states that the total (net) flux of an electric field at points on a closed surface is directly proportional to the electric charge enclosed by that surface.
This ultimately implies that, Gauss's law relates the electric field at points on a closed surface to the net charge enclosed by that surface.
This electromagnetism law was formulated in 1835 by famous scientists known as Carl Friedrich Gauss.
Mathematically, Gauss's law is given by this formula;
ϕ = (Q/ϵ0)
Where;
ϕ is the electric flux.
Q represents the total charge in an enclosed surface.
ε0 is the electric constant.
Answer:
The volume is decreasing at 160 cm³/min
Explanation:
Given;
Boyle's law, PV = C
where;
P is pressure of the gas
V is volume of the gas
C is constant
Differentiate this equation using product rule:
Given;
(increasing pressure rate of the gas) = 40 kPa/min
V (volume of the gas) = 600 cm³
P (pressure of the gas) = 150 kPa
Substitute in these values in the differential equation above and calculate the rate at which the volume is decreasing ( );
(600 x 40) + (150 x ) = 0
Therefore, the volume is decreasing at 160 cm³/min
Answer:
λ = 5.65m
Explanation:
The Path Difference Condition is given as:
δ= ;
where lamda is represent by the symbol (λ) and is the wavelength we are meant to calculate.
m = no of openings which is 2
∴δ=
n is the index of refraction of the medium in which the wave is traveling
To find δ we have;
δ=
δ=
δ=
δ=
δ=
δ=
δ= 82.15 -73.68
δ= 8.47
Again remember; to calculate the wavelength of the ocean waves; we have:
δ=
δ= 8.47
8.47 =
λ =
λ = 5.65m