Answer:
α=0.625rad/s^2
v=340m/s
w=10rad/s
θ=320rad
Explanation:
Constant angular acceleration = ∆w/∆t
angular acceleration = 20/32
α=0.625rad/s^2
Linear velocity v=wr
v = 20×17= 340m/s
Average angular velocity
w0+w1/2
w= 0+20/2
w= 20/2
w=10rad/s
What angle did it rotate with
θ=wt
θ= 10×32
=320rad
Answer:
The value is 
Explanation:
From the question we are told that
The current is 
The radius is 
The length of the wire is
\
The resistance is 
The outer surface temperature is 
The average thermal conductivity is 
Generally the heat generated in the stainless steel wire is mathematically represented as


=> 
=> 
Generally the middle temperature is mathematically represented as



Answer:
K = .3941 × 10³ W/m.K
Explanation:
Qcond = K A ΔT÷ L
∴K = Qcond ×L ÷ A ΔT
J ÷ S = P
P = I × V =Qcond
∴Qcond = I × V
= 0.6 A × 110 V
=66 W
L = 0.12 m
ΔT = 8 °C
Qcond =33 V
Area = (πD²) ÷ 4
= [π (4 × 10⁻² )²] ÷ 4
= 1.256 × 10⁻³ m²
∴A = 1.256 × 10 ⁻³³ m²
So K = ( Qcond × L ) ÷ A ΔT
= (33) (0.12 ) ÷ (1.256 ×10⁻³ ) × 8
= 0.3941 × 10³ W/m .K
The correct answer is the correct answer is A
Im pretty sure this is A. i may be incorrect, give brainliest if im correct please!