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Snowcat [4.5K]
3 years ago
11

Which one is the answer ?

Physics
1 answer:
ollegr [7]3 years ago
6 0
It’s blurry the pic




But I think that is the second one
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What is the power output of a pump which can raise 60kg of water height to height of 10m every minute
sattari [20]

Answer:

<h3>Power = Work Done/time</h3>

=> Power = 60×10×10/60

=> Power = 6000/60

=> Power = 100 Watt

Hence the power output of a pump is 100 Watts.

8 0
2 years ago
The stars, Rigel and Betelgeuse, are both found in the constellation, Orion. Rigel is a blue supergiant, and Betelgeuse is a red
sattari [20]

Answer: a

Explanation: The color of a star is linked to its surface temperature. The hotter the star, the shorter the wavelength of light it will emit. The hottest ones are blue or blue-white, which are shorter wavelengths of light. Cooler ones are red or red-brown, which are longer wavelengths.

6 0
3 years ago
A record player turntable initially rotating at 3313 rev/min is braked to a stop at a constant rotational acceleration. The turn
Rus_ich [418]

Answer:

(A) It will take 22 sec to come in rest

(b) Work done for coming in rest will be 0.2131 J              

Explanation:

We have given the player turntable initially rotating at speed of 33\frac{1}{3}rpm=33.333rpm=\frac{2\times 3.14\times 33.333}{60}=3.49rad/sec

Now speed is reduced by 75 %

So final speed \frac{3.49\times 75}{100}=2.6175rad/sec

Time t = 5.5 sec

From first equation of motion we know that '

\alpha =\frac{\omega -\omega _0}{t}=\frac{2.6175-3.49}{4}=-0.158rad/sec^2

(a) Now final velocity \omega =0rad/sec

So time t to come in rest  t=\frac{0-3.49}{-0.158}=22sec

(b) The work done in coming rest is given by

\frac{1}{2}I\left ( \omega ^2-\omega _0^2 \right )=\frac{1}{2}\times 0.035\times (0^2-3.49^2)=0.2131J

4 0
3 years ago
Monochromatic light of wavelength 580 nm passes through a single slit and the diffraction pattern is observed on a screen. Both
Nuetrik [128]

Answer:

Part a)

Width of the slit is

a = 580 nm

Part b)

Ratio of intensity is given as

\frac{I}{I_o} = 0.81

Explanation:

Part a)

As we know by the formula of diffraction we will have

a sin\theta = \lambda

so we have

\theta = 90

\lambda = 580 nm

so we will have

a sin90 = 580 nm

a = 580 nm

Part b)

As we know that the intensity in diffraction pattern is given as

I = I_o (\frac{sin\theta}{\theta})^2

\frac{I}{I_o} = (\frac{sin\theta}{\theta})^2

so for angle 45 degree

\frac{I}{I_o} = (\frac{sin45}{\pi/4})^2

\frac{I}{I_o} = (\frac{sin45}{\pi/4})^2

\frac{I}{I_o} = 0.81

7 0
3 years ago
Raw sewage is raised vertically by 5.49m in the amountof
uranmaximum [27]

Answer:

          P = 1235.7646 W

Explanation:

Given data:

height of raised sewage = 5.49 m

rate of sewage =1.89*10^6 lt/day

density of sewage = 1.050 kg/m^3

power is written as

P = \frac{work}{time}

work  = m g h

m - mass = ( \rho V)

  h -height

mass lifted per day = ( 1.89*10^6)(1.050)

                              = 1984500 kg

time = 24 hours* 3600 seconds per hour

powerP = \frac{( 1984500)(9.8)( 5.49)}{(24)(3600)}

          P = 1235.7646 W

5 0
3 years ago
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