Answer:
Hence, 0.026 can be expressed as
.
Step-by-step explanation:
- Given 0.026
- Use given, move the decimal point so that first factor is greater than or equal to 1 but less than 10 .
- Then count n and write in scientific notation.
Step 1 of 1
Consider 0.026

Decimal has moved 2 places to right.
The power will be negative as original no. is less than 1 .

Answer:
a₁ = -21 (Given)
a₂ = -28
a₃ = -35
a₄ = -42
Step-by-step explanation:
First term a₁ = -21 (Given)
…………………………………
Second term a₂ :
a₂ = 
…………………………………
Third term a₃ :
a₃ = 
…………………………………
Fourth term a₄ :
a₄ = 
Answer:
all real numbers greater than or equal to -1
Step-by-step explanation:
In order to solve this problem we need to know the vertex and the direction its pointing.
First we expand,
x^2-6x+8
To find the x value of the vertex we use this formula (-b/2a).
-(-6)/2(1) = 3
Now we plug 3 in the equation to get the y value,
(3)^2 - 6(3) + 8 = 9 - 18 + 8 = -1
The vertex is (3,-1)
We know the graph points up because x^2 is positive
The vertex is the lowest point, so we now know that -1 is the starting range and if the graph is pointing up, that means all values greater than -1.
This leads to our answer all real numbers greater than or equal to -1.
One line passes through the points (-2,3) and (0,-3) , it means the y intercept is b=-3
and slope m = 

So the equation of line will be 
And the inequality should be 
Or 
And the other line passes through (-2,3) and (0,2)
So the y intercept is b=2
and the slope is 
So the equation of line will be 
Or

So answer is 
For question number 1:The plot H = H(t) is the parabola and it reaches its maximum in the moment when exactly at midpoint between the roots t = 0 and t = 23. At that moment t = 23/2 or 11.5 seconds.
For question number 2:To find the maximal height, just simply substitute t = 11.5 into the quadratic equation. The answer would be 22.9.
For question number 3:H(t) = 0, or, which is the same as -16t^2 + 368t = 0.Factor the left side to get -16*t*(t - 23) = 0.t = 0, relates to the very start of the process, when the ash started its way up.The other root is t = 23 seconds, and it is precisely the time moment when the bit of ash will go back to the ground.