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2 years ago

What will a soccer player need to do to change a ball’s position?

Chemistry

2 answers:

jek_recluse [69]2 years ago

5 0

Answer:

He must set the ball in motion by applying force in the desired direction.

Explanation:

That is how the soccer player will change the ball's position.

Have a good day :)

kati45 [8]2 years ago

4 0

Answer:

4. He must identify the location of the ball.

Explanation:

If a soccer player needs to change his position, then he will need to identify the location of the ball.

hope this helped.

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5. What is another name for Newton’s first law in your own words.

krek1111 [17]

Newton’s first law states that motion stays the same throughout unless changed such as a football being placed on the ground and not moving it stays at rest and the football being thrown stays in motion unless changed by direction.

5 0

3 years ago

Calculate the freezing point of a solution made from 220g of octane (C Hua), molar mass = 114,0 gmol dissolved in 1480 g of benz

stiv31 [10]

Answer: Freezing point of a solution will be $-1.16^0C$

Explanation:

Depression in freezing point is given by:

$\Delta T_f=i\times K_f\times m$

$\Delta T_f=T_f^0-T_f=(5.50-T_f)^0C$ = Depression in freezing point

i= vant hoff factor = 1 (for non electrolyte)

$K_f$ = freezing point constant = $5.12^0C/m$

m= molality

$\Delta T_f=i\times K_f\times \frac{\text{mass of solute}}{\text{molar mass of solute}\times \text{weight of solvent in kg}}$

Weight of solvent (benzene)= 1480 g =1.48 kg

Molar mass of solute (octane) = 114.0 g/mol

Mass of solute (octane) = 220 g

$(5.50-T_f)^0C=1\times 5.12\times \frac{220g}{114.0 g/mol\times 1.48kg}$

$(5.50-T_f)^0C=6.68$

$T_f=-1.16^0C$

Thus the freezing point of a solution will be $-1.16^0C$

3 0

3 years ago

In class we derived the Gibbs energy of mixing for a binary mixture of perfect gases. We also discussed that the same result is

GaryK [48]

Answer:

Attached below

Explanation:

Free energy of mixing = ΔGmix = Gf - Gi

attached below is the required derivation of the

<u>a) Molar Gibbs energy of mixing</u>

ΔGmix = Gf - Gi

hence : ΔGmix = ∩RT ( X1 In X1 + X2 In X2 + X3 In X3 + ------- )

<u>b) molar excess Gibbs energy of mixing</u>

Ni = chemical potential of gas

fi = Fugacity

N°i = Chemical potential of gas when Fugacity = 1

ΔG = RT In ( a2 / a1 )

4 0

3 years ago

How much heat is needed to boil 3,000 mL of water at its boiling point, 100 C?

Karo-lina-s [1.5K]

Answer: 100C of heat is needed.

Explanation: That is the heating point of water

3 0

3 years ago

This for number 8 and 9

3241004551 [841]

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3 years ago