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Leni [432]
2 years ago
7

ASAP What is the pressure in atm of 0.47mol of a gas in a 1.7L container at 276K?

Chemistry
1 answer:
Doss [256]2 years ago
6 0

Answer:

p= 6.26 atm

Explanation:

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If you increase the volume the pressure will decrease.  so the best answer is C
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3 years ago
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An object has a mass of 441 g and a volume
Ratling [72]

Answer:

<h3>The answer is 4.41 g/cm³</h3>

Explanation:

The density of a substance can be found by using the formula

density =  \frac{mass}{volume}  \\

From the question we have

density =  \frac{441}{10}  \\

We have the final answer as

<h3>4.41 g/cm³</h3>

Hope this helps you

6 0
3 years ago
Which of the following describes scientists?
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I believe the answer I’d D

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3 years ago
Calculate the freezing point (in degrees C) of a solution made by dissolving 7.99 g of anthracene{C14H10} in 79 g of benzene. Th
mario62 [17]

<u>Answer:</u> The freezing point of solution is 2.6°C

<u>Explanation:</u>

To calculate the depression in freezing point, we use the equation:

\Delta T_f=iK_fm

Or,

\Delta T_f=i\times K_f\times \frac{m_{solute}\times 1000}{M_{solute}\times W_{solvent}\text{ in grams}}

where,

\Delta T_f = \text{Freezing point of pure solution}-\text{Freezing point of solution}

Freezing point of pure solution = 5.5°C

i = Vant hoff factor = 1 (For non-electrolytes)

K_f = molal freezing point depression constant = 5.12 K/m  = 5.12 °C/m

m_{solute} = Given mass of solute (anthracene) = 7.99 g

M_{solute} = Molar mass of solute (anthracene) = 178.23  g/mol

W_{solvent} = Mass of solvent (benzene) = 79 g

Putting values in above equation, we get:

5.5-\text{Freezing point of solution}=1\times 5.12^oC/m\times \frac{7.99\times 1000}{178.23g/mol\times 79}\\\\\text{Freezing point of solution}=2.6^oC

Hence, the freezing point of solution is 2.6°C

8 0
3 years ago
Would you classify hydrogen as a metal or a non-metal? <br>Explain why.​
Igoryamba

Answer:

HYDROGEN IS A NON METAL.

HYDROGEN IS A GAS ELEMENT

Hydrogen is nonmetallic, except at extremely high pressures, and readily forms a single covalent bond with most nonmetallic elements, forming compounds such as water and nearly all organic compounds.

BRAINLIEST PLEASE, i really need it

5 0
3 years ago
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