The arrow should point in the direction the object is accelerating.
Answer:
x = 541 m
Dt = ?
vi = 12 m/s
vf = 0 (stop)
a = ?
Use vf^2 = vi^2 + 2a(Dx): 0^2 = (12 m/s)^2 + 2a(541 m), a = -144 m^2/s^2, a = -144 m^2/s^2/(1082 m) = -.1331 m/s/s or -.13 m/s/s
Answer:
7,79 seconds
Explanation:
You need to use the acceleration formula. A is acceliration, is change in velocity and t is time.
You need to multiply the formula with t and divide by a and you get
a*t=
t= /a
after that you just need to insert the numbers
change in velocity is 76.4 minus 0.
acceliration is gravitational acceleration which is 9.81.
After that you get
t=76.4/9.81
t= 7,787971458 s
To solve this problem it is necessary to apply the concepts related to work and power.
Remember that work is defined as the force applied on a body - or exerted by it - to travel a certain distance, and that the power is that energy mentioned to perform that activity in a given instance of time.
Mathematically work is defined as
Where
d = Distance
At this case the acceleration is the same that gravitational acceleration
At the same time we have that power is defined as
Replacing our values we have that the Work done was
Now substituting this value at the Power equation we have
Therefore the power that she is supplying is 100W.
The minimum speed needed a non-propelled object to escape from the gravitational influence of a massive body, that is to achieve an infinite distance from it. I think