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tatiyna
3 years ago
15

How much energy must be absorbed by water with a mass of 0.5 kg in order to raise the temperature from 30°C to 65°C? Note: Water

has a specific heat of 4,190 J/kg °C.
Physics
1 answer:
kvasek [131]3 years ago
6 0

Answer:

73325J

Explanation:

Given parameters:

Mass of water  = 0.5kg

Initial temperature  = 30°C

Final temperature  = 65°C

Specific heat capacity  = 4190J/kg°C

Unknown:

Amount of energy absorbed = ?

Solution:

The amount of energy absorbed can be derived using the expression below;

                H  = m c Δt

H is the amount of energy

m is the mass

c is the specific heat

Δt is the change in temperature

      H  = 0.5 x 4190 x (65 - 30 )

     H  = 73325J

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3 0
3 years ago
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\boxed{\boxed{TE = 1100\:Joule}}\end{array}}\qquad\quad\checkmark


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