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tekilochka [14]
2 years ago
15

Give the following capacitor color codes : ORANGE VIOLET YELLOW WHITE RED​

Physics
2 answers:
Juliette [100K]2 years ago
5 0

Answer:Orange: 3Violet: 7Yellow: 4White: 9Red: 2

Explanation: is that what you looking for

avanturin [10]2 years ago
3 0

Answer:

Orange: 3

Violet: 7

Yellow: 4

White: 9

Red: 2

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Let us be two cylindrical conductors connected in parallel, to which a potential difference of V = 170V is applied. The two cond
PSYCHO15rus [73]

The equivalent resistance of the two cylindrical conductors connected in parallel is 466 ohm.

<h3>Resistance</h3>

Resistance is a measure of the opposition to flow of electric current. It is measured in ohms.

It is given by the formula:

R=\rho\frac{l}{A} \\\\where\ l=length,A=area,\rho=resistivity

Given that R₂ = 469 ohm, hence:

R_2=\rho\frac{l_2}{A_2} \\\\469=\rho\frac{l_2}{\pi r_2^2}

But l₁ = 6l₂, r₁ = (1/5)r₂, hence:

R_1=\rho \frac{l_1}{A_1}=\rho *\frac{6l_2}{[\pi (1/5)r_2]^2} =150 * \rho \frac{l_2}{[\pi r_2]^2}=30*469=70350\ ohm

The equivalent resistance (R) is:

R=\frac{R_1R_2}{R_1+R_1}=\frac{469*70350}{469+70350}  =466\ ohm

The equivalent resistance of the two cylindrical conductors connected in parallel is 466 ohm.

Find out more on resistance at: brainly.com/question/17563681

3 0
3 years ago
How simple machines achieve mechanical advantage?
sveta [45]
Simple machines can be assembled quickly and repaired easily.
6 0
3 years ago
______________ waves move perpendicular to their energy transport, while ____________ waves move parallel to their energy transp
Mademuasel [1]
<span>Transverse waves waves move perpendicular to their energy transport, while </span><span>Longitudinal waves</span> waves move parallel to their energy transport.


4 0
3 years ago
A 22kg box slides down a 30.0 degree incline. If there is no friction, what is the acceleration of the box?
Rashid [163]

Answer:

Acceleration of the box is 4.9 m/s².

Explanation:

The free body diagram is shown below.

The weight of the body can be resolved into two mutually perpendicular components as shown. The force responsible for sliding motion of the box along the incline is due to mg\sin \theta acting along the incline.

Therefore, as per Newton's second law of motion,

Net force = mass\times acceleration

Now, net force acting along the incline is only mg\sin \theta

Therefore,

mg\sin \theta=ma\\a=g\sin \theta

Now, g=9.8\textrm{ and } \theta = 30

Therefore, the acceleration of the box is given as:

a=9.8\times \sin(30)=9.8\times 0.5=4.9\textrm{ }m/s^{2}

Acceleration of the box is 4.9 m/s².

6 0
4 years ago
A ball whose mass is 0.4 kg hits the floor with a speed of 8 m/s and rebounds upward with a speed of 6 m/s. Collapse question pa
Colt1911 [192]

Answer:

The  the average magnitude of the force exerted on the ball by the floor 11.2 \times 10^{3} N

Explanation:

Given:

Mass of ball m = 0.4 kg

Initial speed v_{i} = -8 \frac{m}{s}

Rebound speed v_{f} = 6 \frac{m}{s}

Contact time interval \Delta t = 0.5 \times 10^{-3} sec

For finding the average magnitude of the force on the ball by the floor is given by,

   F_{avg}  = \frac{\Delta P}{\Delta t}

Here \Delta P = m (v_{f}- v_{i} )

   F_{avg} = \frac{m (v_{f} -v_{i}  )}{\Delta t}

   F_{avg} = \frac{0.4 \times (6 -( -8 ) )}{0.5 \times 10^{-3} }

   F_{avg} = 11.2 \times 10^{3} N

Therefore, the  the average magnitude of the force exerted on the ball by the floor 11.2 \times 10^{3} N

6 0
3 years ago
Read 2 more answers
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