The answer is C, as there is not increase or decrease in speed during that time frame.
Answer:
Definitely Spinning permanent magnets within an array of fixed permanent magnets
Explanation:
Any relative motion between magnets (be they permanent or electromagnetic) and a coil of wire will induce an electric current in the coil.
What will not induce an electric current is the relative motion between the two coils of wire (because there is no change in magnetic field), or the relative motion between two magnets (there are no coils of wire to induce the current into).
<em>Therefore, spinning permanent magnets within an array of fixed permanent magnets does not induce an electric current.</em>
Explanation:
The Coulomb's law states that the force acting on two charges is directly proportional to the product of charges and inversely proportional to the square of distance between them . Mathematically, it is given by

Where
k is the electrostatic constant
q₁ and q₂ are charges
r is the distance between them.
The SI unit of electric force is Newton. It can be attractive or repulsive. The attraction or repulsion depend on charges. If both charges are positive, the force is repulsive and if both are opposite charges, the force is attractive.
Answer:
1.147 %
Explanation:
= Density of mercury = 
g = Acceleration due to gravity = 9.81 m/s²
h = Height of mercury = 8.69 m
Standard atmospheric pressure = 
6.55 mmHg converting to Pa

Dividing air pressure by the above value

The fraction of atmospheric pressure is 1.147 %