250 milliliters of a concentrated iron (II) ion solution are sitting on the lab bench in need of analysis to determine its exact
concentration of Fe2+ ions. As part of the analysis a 15 mL sample of this solution was diluted to a final volume of 100 mL. The iron (II) ion concentration of the diluted solution was found to be 1.35 x 10-3 mg/mL Fe2+. What was the total number of milligrams of iron (II) that were contained in the original solution? Note that this question is not asking for how many mg/mL of iron (II) where in the original solution, but the total mass of iron contained in the original solution. Hint: You must first calculate the mg/mL of iron (II) in the original solution.
A chemical concentration is defined as an amount of solute per amount of solution. The diluted solution has an iron (II) concentration of 1,35x10⁻³ mg/mL. As the dilution was of 15 mL in 100 mL, the concentration of the original solution is:
1,35x10⁻³ mg/mL × = <em>9,00x10⁻³ mg/mL</em>
As the total volume of the concentrated iron solution is 250 mL, the total mass of this solution is:
In thermodynamics, the triple point of a substance is the temperature and pressure at which the three phases of that substance coexist in thermodynamic equilibrium. It is that temperatureand pressure at which the sublimation curve, fusion curve and vaporisation curve meet.
The periodic table is composed of seven horizontal rows or periods and is numbered between 1 and 7. There is a regular gradation in the properties of elements in the horizontal rows(periods) from left to right. The periodic table is composed of eight vertical columns or groups. They are numbered between 1 to 8.
