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Lapatulllka [165]
2 years ago
6

Write a balanced chemical equation, complete ionic equation and a net ionic equation for Copper lll sulfate and zinc.

Chemistry
1 answer:
Taya2010 [7]2 years ago
4 0

Answer: CuSO4 (aq)+ Zn (s) → Cu (s) + ZnSO4(aq)

Explanation: do you mean copper II sulphate CuSO4?

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Why is it necessary for us to keep our sence organ clean and healthy.​
Feliz [49]

Answer:

it is necessary to keep our sense organ clean and healthy for if don't clean our sense organ clean we may suffer from many disease like if we don't clean eyes we can't see anything, if we don't clean ear we can't listen anything, and if we don't clean nose it hard for breathing, and if we don't cleanour tounge should be dry and become our breathe smell is very bad, and if we don't clean skin we may suffer from many disease and that may we get cancer also.

5 0
3 years ago
If 842 grams of sodium hydroxide reacts with 750.0 grams of aluminum, how many grams of aluminum hydroxide should theoretically
Phantasy [73]

548.55 grams of aluminum hydroxide should theoretically form.

Explanation:

Balanced equation for the reaction:

3 NaOH + Al ⇒ Al(OH)3 +3 Na

DATA GIVEN:

mass of NaOH = 842 grams, atomic mass =39.9 grams/mole

mass of Al = 750 grams, atomic mass = 26.9 grams/mole

aluminum hydroxide theoretical yield = ?

Moles of NaOH reacted

number of moles = \frac{mass}{atomic mass of 1 mole}

putting the values in the equation

NaOH = \frac{842}{39.9}

           = 21.1 MOLES OF NaOH

Al = \frac{750}{26.9}

   = 27.8 moles

from the equation

 from 3 moles of NaOH 1 mole of Al(OH)3 is produced

21.1 moles of NaOH will react to give x moles of Al(OH)3

\frac{1}{3} = \frac{x}{21.1}

7.03 moles of Al(OH)3 is formed.

and

1 mole of Al(OH)3 is formed from 1 mole of Al in the reaction

so, 27.8 Moles will react to give give 27.8 moles of Al(OH)3 limiting reagent of the given reaction is NaOH

mass of Al(OH)3 =7.03 x 78 (atomic mass of Al(OH)3)

          = 548.55 grams

theoretical  yield from the given data is 548.55 grams

3 0
3 years ago
A sample of gas with an initial volume of 12.5 L at a pressure of 784 torr and a temperature of 295 K is compressed to a volume
Kipish [7]

Answer:

Final pressure in (atm) (P1) = 6.642 atm

Explanation:

Given:

Initial volume of gas (V) = 12.5 L

Pressure (P) = 784 torr

Temperature (T) = 295 K

Final volume (V1) = 2.04 L

Final temperature (T1) = 310 K

Find:

Final pressure in (atm) (P1) = ?

Computation:

According to combine gas law method:

\frac{PV}{T} =\frac{P1V1}{T1} \\\\\frac{(784)(12.5)}{295} =\frac{(P1)(2.04)}{310}\\\\33.22 = \frac{(P1)(2.04)}{310}\\\\P1=5,048.18877

⇒ Final pressure (P1) = 5,048.18877 torr

⇒ Final pressure in (atm) (P1) = 5,048.18877 torr / 760

⇒ Final pressure in (atm) (P1) = 6.642 atm

3 0
3 years ago
True or false: Observing a physical property of a substance will change the substances' identity. I NEED IT NOWWWWW
ale4655 [162]
False

only observing chemical property will change its identity
5 0
3 years ago
A three dimensional circular shape
Bond [772]
A three dimensional circular shape would be a sphere :)
4 0
3 years ago
Read 2 more answers
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