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Naddika [18.5K]
3 years ago
15

Goodyear tires are listed with 29.72 psi pressure limits in the summer, with 10.22 L of air. In the winter, however, the volume

decreases to 7.19 L because of the colder weather. What would the be the new pressure?
Chemistry
1 answer:
serg [7]3 years ago
6 0

Answer:

42.24 psi.

Explanation:

From the question given above, the following data were obtained:

Initial pressure (P₁) = 29.72 psi

Initial volume (V₁) = 10.22 L

Final volume (V₂) = 7.19 L

Final pressure (P₂) =?

The final pressure can be obtained by applying the Boyle's law equation as follow:

P₁V₁ = P₂V₂

29.72 × 10.22 = P₂ × 7.19

303.7384 = P₂ × 7.19

Divide both side by 7.19

P₂ = 303.7384 / 7.19

P₂ = 42.24 psi

Therefore, the final pressure is 42.24 psi

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Al(OH)3 + 3 HCl = AlCl3 + 3 H2O
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Answer:

1) 1.235 g.

2) 0.61 g.

Explanation:

  • From the balanced equation:

<em>Al(OH)₃ + 3HCl → AlCl₃ + 3H₂O.</em>

1.0 mol of Al(OH)₃ reacts with 3.0 moles of HCl to produce 1.0 mol of AlCl₃ and 3.0 moles of H₂O.

<em>1) How many grams of HCl can a tablet with 0.880 g of Al(OH)₃ consume? </em>

  • To calculate the amount of HCl needed to consume 0.880 g of Al(OH)₃, we need to calculate the no. of moles of Al(OH)₃:

no. of moles of Al(OH)₃ = mass/molar mass = (0.880 g)/(78.0 g/mol) = 1.13 x 10⁻² mol.

∵ Every 1.0 mol of Al(OH)₃ needs 3.0 moles of HCl to be consumed.

∴ 1.13 x 10⁻² mol of Al(OH)₃ needs (3 x 1.13 x 10⁻² = 3.385 x 10⁻² mol) of HCl.

The no. of grams of HCl = no. of moles of HCl x molar mass of HCl = (3.385 x 10⁻² mol)(36.5 g/mol) = 1.235 g.

<em>2) How much H₂O?</em>

∵ Every 1.0 mol of Al(OH)₃ produces 3.0 moles of H₂O.

∴ 1.13 x 10⁻² mol of Al(OH)₃ produces (3 x 1.13 x 10⁻² = 3.385 x 10⁻² mol) of H₂O.

<em>The no. of grams of H₂O = no. of moles of H₂O x molar mass of H₂O </em>= (3.385 x 10⁻² mol)(18.0 g/mol) = <em>0.6092 g ≅ 0.61 g.</em>

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How is a suspension different from a colloid?
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Answer:

Explanation:

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