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4 years ago

13

Can some one plz answer this question plz it's in the picture and who ever answers it first and correctly will get 50 points and

their question as the best

1 answer:

Cloud [144]4 years ago

7 0

the answer is 78 kilometers.

1 cm=15 kilometers

so, 6 cm is equal to 90 kilometers.

0.8 millimetres is approximately 12 kilometers.

90 kilometers minus 78 kilometers is equal to 12.

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How much water would a 8 ft by 25 ft rectangle hold

ziro4ka [17]

what is the height? in order to calculate the amount of water a rectangular prism can hold, you must know the volume of that rectangular prism, therefore needing three unit factors, including the length, width, and height.... you gave me two factors, the length and the width, so i cannot help you

8 0

3 years ago

1. Kerry wants to paint her bedroom. The wall dimensions are 14 feet by 10 feet for

RideAnS [48]

Answer: 336 sq ft

Step-by-step explanation: what is it even asking?

6 0

3 years ago

The mean of 10 values is 19. If further 5 values are

Leokris [45]

Answer:

22

Step-by-step explanation:

Pretend the 10 values in the first sentence are a,b,c,d,e,f,g,h,i,j

Pretend the addition 5 values is k,l,m,n,o

So the mean of all the 15 data is (a+b+c+d+e+f+g+h+i+j+k+l+m+n+o)/15=20

So the sum of all 15 data is a+b+c+d+e+f+g+h+i+j+k+l+m+n+o=300 since 15(20)=300

Now let's look at the first 10: We have their mean so we can write:

(a+b+c+d+e+f+g+h+i+j)/10=19

so a+b+c+d+e+f+g+h+i+j=190 since 10(19)=190

So that means using our first sum equation and our equation sum equation we have

190+k+l+m+n+o=300

k+l+m+n+o=300-190

k+l+m+n+o= 110

So the average of those 5 numbers mentioned in your problem is 110/5=22

3 0

3 years ago

2. 10x - 11 - 4x = 43

Nezavi [6.7K]

Answer:

x=9

Step-by-step explanation:

10x - 11 -4x = 43

6x -11 =43

6x = 54

x=9

8 0

4 years ago

Suppose that an airline uses a seat width of 16.5 in. Assume men have hip breadths that are normally distributed with a mean of

Alexxx [7]

Answer:

a) 0.018

b) 0

Step-by-step explanation:

We are given the following information in the question:

Mean, μ = 14.4 in

Standard Deviation, σ = 1 in

We are given that the distribution of breadths is a bell shaped distribution that is a normal distribution.

Formula:

$z_{score} = \displaystyle\frac{x-\mu}{\sigma}$

a) P(breadth will be greater than 16.5 in)

P(x > 16.5)

$P( x > 16.5) = P( z > \displaystyle\frac{16.5 - 14.4}{1}) = P(z > 2.1)$

$= 1 - P(z \leq 2.1)$

Calculation the value from standard normal z table, we have,

$P(x > 16.5) = 1 - 0.982 = 0.018 = 1.8\%$

0.018 is the probability that if an individual man is randomly selected, his hip breadth will be greater than 16.5 in.

b) P( with 123 randomly selected men, these men have a mean hip breadth greater than 16.5 in)

Formula:

$z_{score} = \displaystyle\frac{x-\mu}{\frac{\sigma}{\sqrt{n}}}$

P(x > 16.5)

$P( x > 16.5) = P( z > \displaystyle\frac{16.5-14.4}{\frac{1}{\sqrt{123}}}) = P(z > 23.29)$

$= 1 - P(z \leq 23.29)$

Calculation the value from standard normal z table, we have,

$P(x > 16.5) = 1 - 1 = 0$

There is 0 probability that 123 randomly selected men have a mean hip breadth greater than 16.5 in

4 0

3 years ago