Calculate the maximum internal crack length allowable for a 7075-T651 aluminum alloy component that is loaded to a stress one-ha
1 answer:
Answer: 0.0033 m = 3.3 mm (0.13 in.)
Explanation:
since this problem requires us to calculate the maximum internal crack length allowable for the 7075-T651
aluminum alloy is given that it is loaded to a stress level equal to one-half of its yield strength.
For this alloy, KIc 24 MPa (22 ksi
); also, σ= σ_y/2 = (495 MPa)/2 = 248 MPa (36,000 psi).
Now solving for 2ac gives us;
2a_c=2/π (K_IC/γσ)^2=2/π [(24MPa √m)/(1.35)(248MPa) ]^2=0.0033m=3.3mm (0.13 in.)
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- Velocity is a measure of how quickly a distance changes in relation to time. Having both magnitude and direction, velocity is a vector quantity.
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A horizontal jet of water strikes a curved vane as shown in Figure C.1. The external angle of the curved vane is 158°.The mean velocity and volumetric flow rate of the water jet at position 1 are 12 m/s and 55 m³/h respectively. Due to friction, the water jet leaves the vane at position 2 with 92 % its original velocity.
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