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2 years ago

What is the conversion factor between kg/m^3 and g/m^3. Express your experimental values for the densities in kg/m^3.

Physics

1 answer:

romanna [79]2 years ago

6 0

1000 g = 1 kilog (10³⇒kilo)

so, $\frac{1000 g}{m^{3} }=\frac{1 kg}{m^{3} }$

Since I don't have your values from your experiment, I'm assuming you have your mass values in g. Your teacher wants them in kg, so divide each value (g) by 1000 .

Then divide this mass (now in kg) by your volume in m³. This will make your density units kg/m³

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.physics wave. Please don't dare to answer irrelevant

MAVERICK [17]

Answer:

1a) 857143 m

1b) 414 m

2a)

2b)

3) the medium of air has a wavelength of 0.334 m, the medium of water has a wavelength of 1.493 m, and the medium of 5.130 m.

Explanation:

Question 1a)

Given the velocity/speed, and frequency of the wave, the length can be calculated using these two quantites.

[ λ = v / f ] wavelength = velocity of the wave / frequency of the wave in Hz.

Since 3 × 10^8 × ms^-1 is the velocity, and 350Hz is the frequency.

Anything to the negative power is reciprocated. i.e ms^-1 = m/s.

The wavelength is 300000000m/350Hz = 857142.8571428..... m ≈ 857143 m

Question 1b) Given that the frequency of the second wave in water is 1% of the first wave, and the speed of the second wave is 1450ms^-1

Therefore the second wave has a frequency of 1% of 3.5 = 350/100 Hz = 3.5 Hz

The wavelength is found using the same

formula: wavelength = 1450m/3.5Hz = 414.2857142857.... m ≈ 414 m

Question 2a)

Question 2b)

Question 3) Remember, the speed of sound of the medium = frequency of the medium × wavelength of the medium.

Therefore the wavelength of the medium = speed of sound of the medium / frequency of the medium. This has a similar correlation to the wavelength formula. We are given that all these mediums have a frequency of 1KHz = 1000Hz, where So the wavelength of each medium =

Question 4)

3 0

3 years ago

What is terminal velocity and when is it reached?

Ne4ueva [31]

Terminal velocity is the velocity at which a falling body experience when its weight is equal to the force resistance of force opposing the fall.

At terminal velocity the acceleration of the body is zero, which implies that the value of the this velocity is a uniform.

8 0

3 years ago

Two protons (each with q = 1.60 x 10-19)

otez555 [7]

Answer:

230.4 N

Explanation:

From the question given above, the following data were obtained:

Charge (q) of each protons = 1.6×10¯¹⁹ C

Distance apart (r) = 1×10¯¹⁵ m

Force (F) =?

NOTE: Electric constant (K) = 9×10⁹ Nm²/C²

The force exerted can be obtained as follow:

F = Kq₁q₂ / r²

F = 9×10⁹ × (1.6×10¯¹⁹)² / (1×10¯¹⁵)²

F = 9×10⁹ × 2.56×10¯³⁸ / 1×10¯³⁰

F = 2.304×10¯²⁸ / 1×10¯³⁰

F = 230.4 N

Therefore, the force exerted is 230.4 N

5 0

2 years ago

A 28 kg student stand on the surface of the Earth. What is the magnitude of the

Contact [7]

Answer:

F = 274.68[N]

Explanation:

The gravitational force is equal to the weight of a body, or this case that of a person. Weight can be calculated by means of the product of mass by gravitational acceleration. In this way we have the following equation:

$F=m*g$