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Marrrta [24]
3 years ago
9

Using the rules for significant figures, what do you get when you subtract 15.54 from 508.9538? A. 493 B. 493.4 C. 493.41 D. 493

.413 E. 493.4138
Physics
2 answers:
SpyIntel [72]3 years ago
6 0

Answer:

C). 493.41

Explanation:

As we know that when we subtract the two numbers then the result must contain least number of precise value

or we can say it should contain least number of digits after decimal given in the question

so here we have

508.9538  =  it has 4 digits after decimal

15.54 = it has two digits after decimal

so here we will say that after the difference of two numbers the result must have two digits after decimal

so we have

508.9538 - 15.54 = 493.4138

now rounding it off for two digits after decimal

so it is 493.41

IceJOKER [234]3 years ago
5 0

You get 493.41 when you subtract 15.54 from 508.953 using the rules for significant figures.

 

For addition and subtraction, look at the decimal portion (i.e., to the right of the decimal point) of the numbers ONLY. Here is what to do:

1) Count the number of significant figures in the decimal portion of each number in the problem. (The digits to the left of the decimal place are not used to determine the number of decimal places in the final answer.)

2) Add or subtract in the normal fashion.

3) Round the answer to the LEAST number of places in the decimal portion of any number in the problem.

 

 

The correct answer between all the choices given is the third choice or letter C. I am hoping that this answer has satisfied your query and it will be able to help you in your endeavor, and if you would like, feel free to ask another question.

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Answer:

141.30grams

Explanation:

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Mass is impulse divided by change in velocity:

m=\frac{J}{v-u}\\=\frac{1.3}{5.4--3.8}\\\\=\frac{1.3}{9.2}\\=0.1413Kgs

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3 0
3 years ago
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frozen [14]

Answer:

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6 0
3 years ago
This isn’t homework related but what methods do you guys recommend for shifting realities ? .I’ve tried the raven method for wee
elena55 [62]

Answer:

subs

Explanation:

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6 0
3 years ago
A World War II bomber flies horizontally over level terrain, with a speed of 287 m/s relative to the ground and at an altitude o
Scorpion4ik [409]

Answer: 7.38 km

Explanation: The attachment shows the illustration diagram for the question.

The range of the bomb's motion as obtained from the equations of motion,

H = u(y) t + 0.5g(t^2)

U(y) = initial vertical component of velocity = 0 m/s

That means t = √(2H/g)

The horizontal distance covered, R,

R = u(x) t = u(x) √(2H/g)

Where u(x) = the initial horizontal component of the bomb's velocity = 287 m/s, H = vertical height at which the bomb was thrown = 3.24 km = 3240 m, g = acceleration due to gravity = 9.8 m/s2

R = 287 √(2×3240/9.8) = 7380 m = 7.38 km

6 0
3 years ago
A child walks due east on the deck of a ship at 2 miles per hour. the ship is moving north at a speed of 18 miles per hour. find
garik1379 [7]
Refer to the figure shown below.

The velocity of the child and the velocity of the ship should be added vectorially to find the speed and direction of the child relative to the water surface.

The magnitude of the child's velocity is
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Answer:
The magnitude is 18.1 mph.
The direction is 84° north of east.

8 0
3 years ago
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