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lukranit [14]
3 years ago
15

Which sport requires the least amount of agility? HELLLLPPP

Physics
1 answer:
ZanzabumX [31]3 years ago
5 0

Answer:

golf

Explanation:

it's less physical strength in more of you hitting the ball with whatever the stick is called

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One mole of a substance contains 6.02 × 1023 protons and an equal number of electrons. If the protons could somehow be separated
Aleksandr [31]

Explanation:

it is almost zero .this is because the distance and the electrostatic force are inversely proportional

8 0
2 years ago
A car is initially travelling at 12.1m/s It accelerates at a rate of -3.9m/s^2 for 7 seconds. What is it’s final velocity?
rosijanka [135]
It will be traveling in the reverse direction it was originally going at 15.2 m/s
8 0
3 years ago
At a certain instant a particle is moving in the +x direction with momentum +8 kg m/s. During the next 0.13 seconds a constant f
jeka94

Answer:

The momentum of the particle at the end of the 0.13 s time interval is 7.12 kg m/s

Explanation:

The momentum of the particle is related to force by the following equation:

Δp = F · Δt

Where:

Δp =  change in momentum = final momentum - initial momentum

F = constant force.

Δt = time interval.

Let´s calculate the x-component of the momentum after the 0.13 s:

final momentum - 8 kg m/s = -7 N · 0.13 s

final momentum = -7 kg m/s² · 0.13 s + 8 kg m/s

final momentum = 7.09 kg m/s

Now let´s calculate the y-component of the momentum vector after the 0.13 s. Since the particle wasn´t moving in the y-direction, the initial momentum in this direction is zero:

final momentum = 5 kg m/s² · 0.13 s

final momentum = 0.65 kg m/s

Then, the mometum vector will be as follows:

p = (7.09 kg m/s,  0.65 kg m/s)

The magnitude of this vector is calculated as follows:

|p| = \sqrt{(7.09 kg m/s)^{2} + (0.65 kg m/s)^{2}} = 7.12 kg m/s

The momentum of the particle at the end of the 0.13 s time interval is 7.12 kg m/s

4 0
3 years ago
Which of these galaxies would you most likely find at the center of a large cluster of galaxies?
Arada [10]

Answer:

b. a large elliptical galaxy

Explanation:

In elliptical galaxies the stars are grouped in an elliptical shape, it has a low quantity of gas and dust in comparison to spiral galaxies, and its stars belong to an old population, there is not new stellar formation in it.

The stars orbit in a messy way which made to believe that they form from the merger of galaxies.

They are also really massive (around 10^{4} solar masses).

The most massive and luminous can be found in the center of cluster of galaxies.  

4 0
3 years ago
En la figura los émbolos son de masa despreciable y están en reposo, como se ve en la figura, siendo M=300 kg. Determine: a) la
Leni [432]

The image mentioned is in the attachment

Answer: a) P = 2450 Pa;

b) P = 2940 Pa;

c) F = 4.9 N

Explanation:

a) Pressure is a force applied to a surface of an object or fluid per unit area.

The image shows a block applying pressure on the large side of the piston. The force applied is due to gravitation, so:

P = \frac{F}{A}

P = \frac{m.g}{A}

P = \frac{300.9.8}{1.2}

P = 2450 Pa

The pressure generated by the block is P = 2450 Pa.

b) A static liquid can also exert pressure and can be calculated as:

P_{staticfluid} =ρ.g.h

where

ρ is the density of the fluid

h is the depth of the fluid

g is acceleration of gravity

P_{staticfluid} = 600.9.8.0.5

P_{staticfluid} = 2940 Pa

The pressure in the fluid at 50 cm deep is P_{staticfluid} = 2940 Pa.

c) For the system to be in equilibrium both pressures, pressure on the left side and pressure on the right side, have to be the same:

P_{s} = P_{b}

\frac{F}{A_s} = \frac{F_b}{A_b}

F = \frac{F_b}{A_b}.A_s

Adjusting the units, A_{s} = 0.002 m².

F = \frac{300.9.8.0.002}{1.2}

F = 4.9 N

The force necessary to be equilibrium is F = 4.9 N.

4 0
2 years ago
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