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2 years ago

Which sport requires the least amount of agility? HELLLLPPP

Physics

1 answer:

ZanzabumX [31]2 years ago

5 0

Answer:

golf

Explanation:

it's less physical strength in more of you hitting the ball with whatever the stick is called

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Which arrow best represents the path of an object with projectile motion?

Fittoniya [83]

C because it's non linear

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3 years ago

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Tim and Rick both can run at speed Vr and walk at speed Vw, with Vr > Vw.

miss Akunina [59]

Answer:

Δt = $\frac{2D}{Vw+Vr} - \frac{D}{2Vr} - \frac{D}{2Vw}$

Explanation:

Hi there!

Using the equation of speed for the whole trip, we can obtain the time each one needed to cover the distance D.

The speed (v) is calculated by dividing the traveled distance (d) over the time needed to cover that distance (t):

v = d/t

Rick traveled half of the distance at Vr and the other half at Vw. Then, when v = Vr, the distance traveled was D/2 and the time is unknown, Δt1:

Vr = D/ (2 · Δt1)

For the other half of the trip the expression of velocity will be:

Vw = D/(2 · Δt2)

The total time traveled is the sum of both Δt:

Δt(total) = Δt1 + Δt2

Then, solving the first equation for Δt1:

Vr = D/ (2 · Δt1)

Δt1 = D/(2 · Vr)

In the same way for the second equation:

Δt2 = D/(2 · Vw)

Δt + Δt2 = D/(2 · Vr) + D/(2 · Vw)

Δt(total) = D/2 · (1/Vr + 1/Vw)

The time needed by Rick to complete the trip was:

Δt(total) = D/2 · (1/Vr + 1/Vw)

Now let´s calculate the time it took Tim to do the trip:

Tim walks half of the time, then his speed could be expressed as follows:

Vw = 2d1/Δt Where d1 is the traveled distance.

Solving for d1:

Vw · Δt/2 = d1

He then ran half of the time:

Vr = 2d2/Δt

Solving for d2:

Vr · Δt/2 = d2

Since d1 + d2 = D, then:

Vw · Δt/2 + Vr · Δt/2 = D

Solving for Δt:

Δt (Vw/2 + Vr/2) = D

Δt = D / (Vw/2 + Vr/2)

Δt = D/ ((Vw + Vr)/2)

Δt = 2D / (Vw + Vr)

The time needed by Tim to complete the trip was:

Δt = 2D / (Vw + Vr)

Let´s find the diference between the time done by Tim and the one done by Rick:

Δt(tim) - Δt(rick)

2D / (Vw + Vr) - (D/2 · (1/Vr + 1/Vw))

$\frac{2D}{Vw+Vr} - \frac{D}{2Vr} - \frac{D}{2Vw}$ = Δt

Let´s check the result. If Vr = Vw:

Δt = 2D/2Vr - D/2Vr - D/2Vr

Δt = D/Vr - D/Vr = 0

This makes sense because if both move with the same velocity all the time both will do the trip in the same time.

8 0

3 years ago

After asking a question, a scientist can form a(n) , which is an idea that may be proved or disproved by an experiment.

DochEvi [55]

Answer:

When scientists have a question, they form a hypothesis, which is an idea that may be proved or disproved by an experiment.

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3 years ago

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Select the correct answer from the drop-down menu. anne applies a force on a toy car and makes it move forward. what can be said

nalin [4]

Answer:

The forces could be gravity, friction between the car and the ground, the force Katie is applying and the normal reaction.

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1 year ago

In an oscillating LC circuit, the total stored energy is U and the maximum current in the inductor is I. When the current in the

Deffense [45]

Answer:

The definition of that same given problem is outlined in the following section on the clarification.

Explanation:

The Q seems to be endless (hardly any R on the circuit). So energy equations to describe and forth through the inducer as well as the condenser.

Presently take a gander at the energy stored in your condensers while charging is Q.

⇒ $U =\frac{Qmax^2}{C}$

So conclude C doesn't change substantially as well as,

When,

⇒ $Q=\frac{Qmax}{2}$

⇒ $Q^2=\frac{Qmax^2}{4}$

And therefore only half of the population power generation remains in the condenser that tends to leave this same inductor energy at 3/4 U.

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3 years ago