1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Sauron [17]
2 years ago
9

Pls help I’ll mark brainliest pls pls pls

Chemistry
2 answers:
katovenus [111]2 years ago
7 0
The tea was no longer hot or (brewed) so the 5th didn’t dissolve like the others because the tea was hot or warm enough anymore it cooled down. So the sugar won’t dissolve no more.
horsena [70]2 years ago
5 0

Answer:

the tea was not hot sugar dissolves quickly and hot water than cold

You might be interested in
Calculate the amount of CO2 produced when 1.00 mole of propane (C3H8) is burned in the presence of 1.00 mole of oxygen.
Anna [14]

<u>Answer:</u>

The balanced Chemical equation is

1C_3 H_8  +5O_2  >3CO_2+4H_2 O

Since quantity of two reactants are given Hence we find the moles of product using both.

The quantity of product produced is the one we consider from the limiting reactant.

Limiting reactant is the reactant which runs out first.

So, least product is produced from the limiting reactant.

Mole ratio of C_3 H_8:CO_2 is 1: 3

$1.00 \mathrm{mol} \mathrm{C}_{3} \mathrm{H}_{\mathrm{8}} \times \frac{3 \mathrm{mol} \mathrm{CO}_{2}}{1 \mathrm{mol} \mathrm{C}_{3} \mathrm{H}_{8}}=3 \mathrm{molCO}_{2}$

Mole ratio of O_2:CO_2 is 5: 3

$1.00 \mathrm{mol} \mathrm{O}_{2} \times \frac{3 \mathrm{mol} \mathrm{co}_{2}}{5 \mathrm{mol} \mathrm{O}_{2}}=0.6 \mathrm{mol} \mathrm{CO}_{2}$

(Least produced)

So, the limiting reactant is O_2

The amount of CO_2 formed is 0.600mol (Answer)

4 0
3 years ago
Describe the symmetry of a cubic crystal?
alukav5142 [94]

Answer:

It is an imaginary plane which passes through the molecule and divides it into portions which are exactly the superimposable mirror images of each other.

4 0
2 years ago
Read 2 more answers
In the commercial manufacture of nitric acid, how many liters of nitrogen dioxide will produce 30 liters of nitric oxide given t
LiRa [457]
2NO + O₂ = 2NO₂

V(NO)=30 L

V(NO₂)=V(NO)=30 L
5 0
2 years ago
How much energy is added to change 180g of liquid water to gas at 100 degrees Celsius
Finger [1]

Answer:

40.7 kJ  

Step-by-step explanation:

The formula for the heat, q, needed to evaporate a liquid is

q = mΔHvap


<em>Data:  </em>

        m = 180 g

ΔHvap = 2260 J/g

<em>Calculation: </em>

q = 180 g × 2260 /1

q = 40 700 J = 40.7 kJ

7 0
3 years ago
13.8g element consist 4.6 ×10^22 atoms what is atomic mass of element?​
Keith_Richards [23]
<h2>~<u>Solution</u> :-</h2>
  • Here, to find the atomic mass of element, we must;

We know that,

  • 4.6 x $ \sf{10^{22}}$ atoms of an element weigh 13.8g.

Thus,

The atoms of $ \sf{ 6.02 \times 10^{13}}$ will weigh;

=   \sf{\frac{13.8  \times 6.02 \times  {10}^{23} }{4.6 \times {10}^{22} } } \\

=  \sf{180.6 \: g \:  \: (molar \: mass)}

  • Hence, the molar mass (atomic mass) will be <u>180.6 g.</u>
8 0
2 years ago
Read 2 more answers
Other questions:
  • Help plz i don't know this
    8·1 answer
  • Solution that has a ph below 7.0 tastes sour is called
    9·1 answer
  • How does adversity lead to change?​
    6·1 answer
  • Compared to an atom of hydrogen in the ground state, an atom of hydrogen in the excited state has
    8·1 answer
  • What is the octet rule
    12·2 answers
  • he atomic number of fluorine is 9. How many electrons does an ion of fluorine have if it is represented by the symbol shown belo
    11·2 answers
  • Can you always tell by looking at a substance if it is pure or not? ​
    10·1 answer
  • Calculate the atoms of hydrogen in 52.0 g of H2O.
    12·1 answer
  • A scientist performed an experiment with a mouse where the mouse was moving along a track with a new experimental unscented chee
    14·1 answer
  • Moving electrons are found to exhibit properties of.
    14·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!