All categories

2 years ago

Pls help I’ll mark brainliest pls pls pls

Chemistry

2 answers:

katovenus [111]2 years ago

7 0

The tea was no longer hot or (brewed) so the 5th didn’t dissolve like the others because the tea was hot or warm enough anymore it cooled down. So the sugar won’t dissolve no more.

horsena [70]2 years ago

5 0

Answer:

the tea was not hot sugar dissolves quickly and hot water than cold

You might be interested in

An orbital would never exist in the quantum description of an atom is

Mamont248 [21]

Hydrogen i think. the orbital of hydrogen is peculiar

6 0

3 years ago

Twenty-seven milliliters of an acid with an unknown concentration are titrated with a base that has a concentration of 0.55 M. T

Svetllana [295]

It should be 0.25 M. Use the formula C1*V1=C2*V2, for those values, as it is right when it changed colour. Remember to change the if those are not the same (but in your case it is, so no need this time).

C1*V1=C2*V2
C1*27ml=0.55M*12.5ml
C1=(0.55M*12.5ml)/27ml = 0.25M

4 0

3 years ago

Read 2 more answers

The empirical formula of styrene is CH; its molar mass is 104.1 g/mol. What is the molecular formula of styrene

frez [133]

The atomic mass of carbon is 12.011 g/mol.
The atomic mass of hydrogen is 1.00794 g/mol.

This means the molar mass of CH is

$12.011+1.00794=13.01894 \text{ g/mol}$

Dividing the given molar mass by this, $\frac{104.1}{13.01894} \approx 8$

This means the molecular formula is $\boxed{\text{C}_{8}\text{H}_{8}}$

7 0

2 years ago

In which pair would both compounds have the same empirical formula? A. H2O and H2O2 B. BaSO4 and BaSO3 C. FeO and Fe2O3 D. C6H12

Kazeer [188]

The pair of both compounds that have the same empirical formula are C6H12O6 and HC2H3O2. The answer is letter D. H2O and H2O2, BaSO4 and BaSO3 and FeO and Fe2O3 do not have the same empirical formula.

4 0

3 years ago

A solution is known to contain only one type of cation. Addition of Cl1- ion to the solution had no apparent effect, but additio

zhannawk [14.2K]

Answer:

We can have: Calcium, strontium, or barium

Explanation:

In this case, we have to remember the solubility rules for sulfate $SO_4~^-^2$ and the chloride $Cl^-$ :

Sulfate

All sulfate salts are SOLUBLE-EXCEPT those also containing: Calcium, silver, mercury (I), strontium, barium or lead.( $Ca^+^2~,Ag^+~,Hg_2^+^2~,Sr^+2~,Ba^+^2~,Pb^+^2$ ), which are NOT soluble.

Chloride

All chloride salts as SOLUBLE-EXCEPT those also containing: lead, silver, or mercury (I). ( $Pb^+^2~,Ag^+~,Hg_2~^+^2$ ), which are NOT soluble.

If we the salt formed a precipitated with the sulfate anion, we will have as possibilities "Calcium, silver, mercury (I), strontium, barium or lead". If We dont have any precipitated with the Chloride anion we can discard "Silver, mercury (I), lead" and our possibilities are:

"Calcium, strontium, or barium".

I hope it helps!

7 0

3 years ago