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LekaFEV [45]
2 years ago
10

Which of the following changes would decrease the coefficient of friction needed for this ride?

Physics
1 answer:
posledela2 years ago
7 0
Friction occurs between two contacting surfaces. The coefficient of friction is very much dependent on the roughness of these surfaces. Some of the many ways in which the coefficient can be lessened or decreased are to lubricate the surface or make it shiny by eliminating the spikes which caused the roughness. 
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You have a small piece of iron at 75 °C and place it into a large container of water at 25 °C. Which of these best explains what
svp [43]
D. Heat energy will be transferred within the system and if left long enough, there will be enough transferred energy to make both of them the same temperature.
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2 years ago
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An ion accelerated through a potential difference of 115 V experiences an increase in kinetic energy of 7.37 x 1017 J. Calculate
riadik2000 [5.3K]

Answer: 6.408(10)^{-19} C

Explanation:

This problem can be solved by the following equation:

\Delta K=q V

Where:

\Delta K=7.37(10)^{-17} J is the change in kinetic energy

V=115 V is the electric potential difference

q is the electric charge

Finding q:

q=\frac{\Delta K}{V}

q=\frac{7.37(10)^{-17} J}{115 V}

Finally:

q=6.408(10)^{-19} C

4 0
3 years ago
The actual mechanical advantage of any machine is its__________divided by its________________
zaharov [31]

Answer: Load divided by it effort

Explanation:

Mechanical advantage of any machine is its load divided by its effort

4 0
3 years ago
Why do you think energy usage is different at different times of the day
g100num [7]
People are asleep at 3 am so energy would be less then.
7 0
3 years ago
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A 35.4 kg girl is riding on the back of a 15.23 kg cart. the cart and the kid are both moving eastward at 4.25 m/s when she step
Grace [21]

Answer:

The final  velocity of the cart is  v_c = 7.02 \  m/s

Explanation:

From the question we are told that

    The mass of the girl is  m_g  = 35.4 \ kg

     The mass of the cart is  m_c  = 15.23 \ kg

      The speed of the cart and  kid(girl) is  v = 4.25 \ m/s

     The final velocity of  the girl is v_g  = 3.06 \  m/s

Let assume that velocity eastward is  positive and velocity westward is negative (Note that if we assume vise versa it wouldn't affect the answer )

   The total momentum of the system before she steps off the back of the cart

is mathematically evaluated as

        p__{T1}} = (m_g + m_c) * v

substituting values

        p__{T1}} = (35.4 + 15.23) * 4.25

        p__{T1}} =215.17 \  kg m /s

The total momentum after she steps off the back of the cart is mathematically evaluated as

        p__{T2}} = (m_g * v_g ) +(  m_c * v_c )

Where  v_c  is the final velocity of the cart

substituting values    

      p__{T2}} = (35.4 * 3.06 ) +(  15.23 * v_c )

       p__{T2}} = 108. 324 + 15.23  v_c

Now according to the law of conservation of momentum

       p__{T1}} =p__{T2}}

So  

       215.17 \  kg m /s =  108. 324 + 15.23  v_c

=>      v_c = 7.02 \  m/s

Since the value is positive it implies that the cart moved eastward

7 0
3 years ago
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