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2 years ago

10

Which of the following changes would decrease the coefficient of friction needed for this ride?

1 answer:

posledela2 years ago

7 0

Friction occurs between two contacting surfaces. The coefficient of friction is very much dependent on the roughness of these surfaces. Some of the many ways in which the coefficient can be lessened or decreased are to lubricate the surface or make it shiny by eliminating the spikes which caused the roughness.

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A car is traveling in a race.The car went from initial velocity of 35m/s to the final velocity of 65m/s in 5 seconds what was th

I am Lyosha [343]

Acceleration is the change in velocity divided by time. The change in velocity is -30m/s and time is 5s. If you divide -30m/s by 5s, you get -6m/s<span>².</span>

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2 years ago

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Which statements accurately describe Dmitri Mendeleev’s contributions to the development of the periodic table? Check all that a

Mama L [17]

Mendeleev produced the first orderly arrangement of known elements. Mendeleev used patterns to predict undiscovered elements.

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Scientific work is currently underway to determine whether weak oscillating magnetic fields can affect human health. For example

nlexa [21]

Answer:

The maximum emf that can be generated around the perimeter of a cell in this field is $1.5732*10^{-11}V$

Explanation:

To solve this problem it is necessary to apply the concepts on maximum electromotive force.

For definition we know that

$\epsilon_{max} = NBA\omega$

Where,

N= Number of turns of the coil

B = Magnetic field

$\omega =$ Angular velocity

A = Cross-sectional Area

Angular velocity according kinematics equations is:

$\omega = 2\pi f$

$\omega = 2\pi*61.5$

$\omega =123\pi rad/s$

Replacing at the equation our values given we have that

$\epsilon_{max} = NBA\omega$

$\epsilon_{max} = NB(\pi (\frac{d}{2})^2)\omega$

$\epsilon_{max} = (1)(1*10^{-3})(\pi (\frac{7.2*10^{-6}}{2})^2)(123\pi)$

$\epsilon_{max} = 1.5732*10^{-11}V$

Therefore the maximum emf that can be generated around the perimeter of a cell in this field is $1.5732*10^{-11}V$

6 0

3 years ago

A rat is pushed with a massive force. The mass of the rat is 2.3 kg and the acceleration of the rat is 9.5 m/s^2. What was the f

Phoenix [80]

Answer:

Force = 21.85N

Explanation:

Given the following data;

Mass = 2.3kg

Acceleration = 9.5m/s²

To find the force;

Force is given by the multiplication of mass and acceleration.

Mathematically, Force is;

$F = ma$

Where;

F represents force.

m represents the mass of an object.

a represents acceleration.

Substituting into the equation, we have

Force = 2.3 * 9.5

Force = 21.85N

Therefore, the force applied to the rat is 21.85 Newton.

8 0

2 years ago

Y_Kistochka [10]

Answer:

F = 17.3 kN

Explanation:

The normal force must support the weight of the car plus provide for the needed centripetal acceleration.

F = m(g + v²/R ) = 1000(9.8 + 15²/30) = 17,300

6 0

2 years ago