Question

A projectile fired from a gun has initial horizontal and vertical components of velocity equal to 30 m/s and 40 m/s, respectively. 3. Approximately how long does it take the projectile to reach the highest point in its trajectory

Answer 1

Answer:

The time is 5.10 sec.

Explanation:

Given that,

Component of velocity are 30 m/s and 40 m/s.

We need to calculate the resultant velocity

Using formula of resultant velocity

$v=\sqrt{v_{x}^2+v_{y}^2}$

Put the value into the formula

$v=\sqrt{(30)^2+(40)^2}$

$v=50\ m/s$[

We need to calculate the time

Using equation of motion

$v = u+gt$

$v = 0+gt$

$t=\dfrac{v}{g}$

Put the value into the formula

$t=\dfrac{50}{9.8}$

$t=5.10\ sec$

Hence, The time is 5.10 sec.