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nikklg [1K]
3 years ago
6

How does the time of flight differ between an object launched from a height parallel to ground and an object launched from the g

round with an angle of elevation ?
Physics
1 answer:
cestrela7 [59]3 years ago
5 0

Answer:

Y = Vy t - 1/2 g t^2       height Y after time t

Y1 = -1/2 g t^2     object launched with no vertical velocity

Y2 = Vy t - 1/2 g t^2   object launched with vertical speed Vy

Obviously Y2 is greater than Y1

Y1 will reach a given negative vertical height sooner than Y2

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Models can help us experiment with the motions of objects in space, which are determined by the gravitational pull between them.

Explanation:

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water vapor contained in a piston–cylinder assembly undergoes an isothermal expansion at 240°c from a pressure of 7 bar to a pre
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7 0
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Anyone know a GOOD show on Netflix please kid shows pleaseeeee
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The coded height at North Platte, in west-central Nebraska, ("557") indicated 500 mb occurred at 5,570 meters above sea level.

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