How does the time of flight differ between an object launched from a height parallel to ground and an object launched from the g

Question

3 years ago

6

round with an angle of elevation ?

1 answer:

cestrela7 [59] · Answer 1 · 2022-08-31T03:36:00+03:00

Answer:

Y = Vy t - 1/2 g t^2 height Y after time t

Y1 = -1/2 g t^2 object launched with no vertical velocity

Y2 = Vy t - 1/2 g t^2 object launched with vertical speed Vy

Obviously Y2 is greater than Y1

Y1 will reach a given negative vertical height sooner than Y2