Answer:
![\boxed {\tt 3.6 \ seconds}](https://tex.z-dn.net/?f=%5Cboxed%20%7B%5Ctt%203.6%20%5C%20seconds%7D)
Explanation:
Time can be found by dividing the distance by the speed.
![t=\frac{d}{s}](https://tex.z-dn.net/?f=t%3D%5Cfrac%7Bd%7D%7Bs%7D)
The distance is 45 meters and the speed is 12.5 meters per second.
![d= 45 \ m \\s= 12.5 \ m/s](https://tex.z-dn.net/?f=d%3D%2045%20%5C%20m%20%5C%5Cs%3D%2012.5%20%5C%20m%2Fs)
![t=\frac{45 \ m}{12.5 \ m/s}](https://tex.z-dn.net/?f=t%3D%5Cfrac%7B45%20%5C%20m%7D%7B12.5%20%5C%20m%2Fs%7D)
Divide. Note that the meters, or "m" will cancel each other out.
![t=\frac{45 }{12.5 \ s}](https://tex.z-dn.net/?f=t%3D%5Cfrac%7B45%20%7D%7B12.5%20%5C%20s%7D)
![t=3.6 \ s](https://tex.z-dn.net/?f=t%3D3.6%20%5C%20s)
It will take the dolphin 3.6 seconds to swim a distance of 45 meters are 12.5 meters per second.
Explanation:
There are two components of a longitudinal sound wave which are compression and rarefaction. Similarly, there are two components of the transverse wave, the crest, and trough.
The crest of a wave is defined as the part that has a maximum value of displacement while the trough is defined as the part which corresponds to minimum displacement.
While compression is that space where the particles are close together while the rarefaction is that space where the particles are far apart from each other.
So, the refraction or the rarefied part of a longitudinal sound wave is analogous to a trough of a transverse wave.
Mater doesn't just appear or disappeared. Chemical elements are still there just the connections and how it combines changes.
So what goes into your chemical eqation must still exist after the change.
Answer:
c. 2 m/s
Explanation:
The relationship between speed, frequency and wavelength of a wave is given by:
![v=f \lambda](https://tex.z-dn.net/?f=v%3Df%20%5Clambda)
where
v is the speed of the wave
f is its frequency
is the wavelength
For the transverse wave in this problem, we have:
is the frequency
is the wavelength
Substituting these numbers into the equation, we find the speed of the wave:
![v=(4 Hz)(0.5 m)=2 m/s](https://tex.z-dn.net/?f=v%3D%284%20Hz%29%280.5%20m%29%3D2%20m%2Fs)
The total work is
(mass of the elevator, kg) x (9.8 m/s²) x (9.0 m) Joules .