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Fofino [41]
4 years ago
15

Which of the following equations is balanced?

Physics
2 answers:
Sav [38]4 years ago
6 0
The answer is B, because if you look, once you add the double hydrogen, that's when you balance out the equation. Hope this helps!  
olasank [31]4 years ago
6 0

Answer:

2H_2 + O_2 --> 2H_2O

Explanation:

If the equation is balanced then it means the number of atoms on the product side is same as the number of atoms on the reactant side.

So here as we can see that the reaction which will have same number of atoms on both sides is given as

2H_2 + O_2 --> 2H_2O

here on reactant side we can see 4 hydrogen atoms are given and 2 Oxygen atoms are present.

So if reaction is balanced then we can see that the number of atoms on product side is also 4 hydrogen atoms and 2 oxygen atoms.

So above reaction is balanced reaction

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3 years ago
A 3 inch fire hose has a water flow of 200 gallons per minute. What is the flow in liters per second? Note: Use US gallons not U
stepladder [879]

Answer:

Case I: 12.617 L/s

Case II: 161.406 cubic meters per hour

Case III: 1.062 Pound inches

Explanation:

<u>Given:</u>

  • Speed of water flow = 200 gallons per minute
  • Speed of air blow = 95 cubic feet per minute
  • Measure of Torque = 12 Newton centimeter

<u>Assumptions:</u>

  • 1 US gallon = 3.785 L
  • 1 min = 60 s
  • 1 ft = 0.3048 m
  • 1 h = 60 min
  • 1 inch = 2.54 cm
  • 1 N = 0.2248 lb

Case I:

Speed\ of\ water\ flow = 200 \dfrac{gallon}{min}\\\Rightarrow V_{water} = 200\times \dfrac{3.785\ L}{60\ s}\\\Rightarrow V_{water} = 12.617\ L/s

Case II:

Speed\ of\ air\ blow = 95 \dfrac{ft^3}{min}\\\Rightarrow V_{air} = 95\times \dfrac{(0.3048\ m)^3}{\dfrac{1}{60}\ h}\\\Rightarrow V_{air} = 95\times (0.3048)^3\times 60\ m^3/h\\\Rightarrow V_{air} = 161.406\ m^3/h

Case III:

Measure\ of\ torque = 12\ N cm\\\Rightarrow \tau = 12\times (0.2248\ lb)\times \dfrac{1}{2.54}\ in\\ \Rightarrow \tau = 1.062\ lb in

6 0
3 years ago
A 0.210-kg metal rod carrying a current of 11.0 A glides on two horizontal rails 0.490 m apart. If the coefficient of kinetic fr
sergij07 [2.7K]

Answer:

The  magnetic field is  B = 0.0764 \ T

Explanation:

From the question we are told that  

    The mass of the metal is  m  =  0.210 \ kg

     The current is  I  =  11.0 \ A

      The distance between the rail(length of the rod ) is  d  =  0.490 \ m

      The coefficient of kinetic friction is  \mu_k  =  0.200

Generally the magnetic force is mathematically represented as

      F_b  =  B *  I  *  d

Given that the rod is moving at a constant velocity, it

=>    F_b  =  F_k

Where F_k is the kinetic frictional force which is mathematically represented as

       F_k  =  \mu_k  *  m *  g

So

    B *  I  *  d =  \mu_k  * m * g

=>   B =  \frac{\mu_k  * m * g}{I  *  d }

substituting values

=>   B =  \frac{0.200  * 0.210  * 9.8 }{ 11  *  0.490 }

=>   B = 0.0764 \ T

3 0
3 years ago
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