definition of breeder reactors.
These are a type of nuclear reactors which produce more fissile material than they consume
Advantages: Breeder reactors produce Pu-239 which can be extensively used as a nuclear fuel. Also, Pu-239 can absorb neutron to form Pu-240, which is another fertile material.[1]
Answer:
frequency of the sound = f = 1,030.3 Hz
phase difference = Φ = 229.09°
Explanation:
Step 1: Given data:
Xini = 0.540m
Xfin = 0.870m
v = 340m/s
Step 2: frequency of the sound (f)
f = v / λ
λ = Xfin - Xini = 0.870 - 0.540 = 0.33
f = 340 / 0.33
f = 1,030.3 Hz
Step 3: phase difference
phase difference = Φ
Φ = (2π/λ)*(Xini - λ) = (2π/0.33)* (0.540-0.33) = 19.04*0.21 = 3.9984
Φ = 3.9984 rad * (360°/2π rad)
Φ = 229.09°
Hope this helps!
Answer:
Explanation: This Law of Superposition is fundamental to the interpretation of Earth history, because at any one location it indicates the relative ages of rock layers and the fossils in them.
Answer:
![E = 1.85*10^{12}\frac{N}{C}](https://tex.z-dn.net/?f=%20E%20%3D%201.85%2A10%5E%7B12%7D%5Cfrac%7BN%7D%7BC%7D%20)
Explanation:
Hi!
The perpendicular distance 2.4cm, is much less than the distance to both endpoints of the wire, which is aprox 1m. Then the edge effect is negligible at this field point, and we can aproximate the wire as infinitely long.
The electric filed of an infinitely long wire is easy to calculate. Let's call z the axis along the wire. Because of its simmetry (translational and rotational), the electric field E must point in the radial direction, and it cannot depende on coordinate z. To calculate the field Gauss law is used, as seen in the image, with a cylindrical gaussian surface. The result is:
![E = \frac{\lambda}{2\pi \epsilon_0 r}\\\lambda=\text{charge per unit length}=\frac{4.95 \mu C}{2 m} = 2.475 \frac{C}{m}\\r=\text{perpendicular distance to wire}\\\epsilon_0=8.85*10^{-12}\frac{C^2}{Nm^2}](https://tex.z-dn.net/?f=E%20%3D%20%5Cfrac%7B%5Clambda%7D%7B2%5Cpi%20%5Cepsilon_0%20r%7D%5C%5C%5Clambda%3D%5Ctext%7Bcharge%20per%20unit%20length%7D%3D%5Cfrac%7B4.95%20%5Cmu%20C%7D%7B2%20m%7D%20%3D%202.475%20%5Cfrac%7BC%7D%7Bm%7D%5C%5Cr%3D%5Ctext%7Bperpendicular%20distance%20to%20wire%7D%5C%5C%5Cepsilon_0%3D8.85%2A10%5E%7B-12%7D%5Cfrac%7BC%5E2%7D%7BNm%5E2%7D)
Then the electric field at the point of interest is estimated as:
![E = \frac{\22.475}{2\pi*( 8.85*10^{-12})*(2.4*10^{-2})}\frac{N}{C}=1.85*10^{12}\frac{N}{C}](https://tex.z-dn.net/?f=E%20%3D%20%5Cfrac%7B%5C22.475%7D%7B2%5Cpi%2A%28%208.85%2A10%5E%7B-12%7D%29%2A%282.4%2A10%5E%7B-2%7D%29%7D%5Cfrac%7BN%7D%7BC%7D%3D1.85%2A10%5E%7B12%7D%5Cfrac%7BN%7D%7BC%7D)