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IRISSAK [1]
3 years ago
6

Define electric potential and inductance using sentences an elementary student could understand. Do not use math

Physics
2 answers:
HACTEHA [7]3 years ago
4 0

Answer and Explanation:

1). Electric Potential:

Electric Potential can be defined as the amount of work required to move a unit  charge from infinity or reference point to a particular or specific point inside the electric field (without any accelerated motion of charge particle). The other terms for electric potential are 'electrostatic potential, potential difference(if a charge is moved from one point to another inside the field) or electric field potential.

2). Inductance:

It can be define as that property of electric circuits due to which it opposes any change in the voltage under the influence of changing magnetic field.

We can also say that the property of an electric conductor due to which it opposes any change in electric current passing through it. Any change in electric current results in the production of magnetic field which when varied results in the generation of Electro Motive Force (EMF) which according to Lenz law is produced in a way that it opposes its cause of production.

Marizza181 [45]3 years ago
3 0

Answer:

Electric - Electric potential energy is the capacity for doing work based on the object's electric charge. Nuclear - The potential energy of the particles inside an atom. Chemical - Chemical potential energy is the energy stored up in substances due to their chemical bonds. or Electric Potential Energy. Potential energy can be defined as the capacity for doing work which arises from position or configuration. In the electrical case, a charge will exert a force on any other charge and potential energy arises from any collection of charges.

Explanation:

links

http://hyperphysics.phy-astr.gsu.edu/hbase/electric/elepe.html

link

https://www.ducksters.com/science/physics/potential_energy.php

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RSB [31]

Answer:separate

Explanation:

6 0
3 years ago
In an experiment, 108 J of work was done on a closed system. During this phase of the experiment, 79 J of heat energy was added
amid [387]

Answer:

187 J

Explanation:

First Law of Thermodynamics :

ΔQ = ΔW + ΔU

ΔQ : Heat. If it added to system then positive and if it is rejected by system then negative.

ΔW : Work. If it done by the system then positive and if it is done on system then negative.

ΔU : Internal Energy. If it positive then temperature of system increased and if it is negative then temperature of system decreased.

ΔQ = 79 J

ΔW = - 108 J

ΔU = ?

substituting the value in the equation:

79 = -108 + ΔU

∴ ΔU = 187 J

7 0
3 years ago
What mass of NH3 can be made from 35.0 grams of N2
Allushta [10]

42.5g

Explanation:

Given parameters:

Mass of N₂= 35g

Unknown:

Mass of NH₃  = ?

Solution:

  Equation of the reaction:

         N₂  +  3H₂  →   2NH₃

To solve this problem, we work from the known species to the unknown. The known here is the reacting mass of the N₂. From this we can find the number of moles of the N₂.

            Number of moles of N₂ = \frac{mass}{molar mass}

molar mass of N₂ = 28g/mol

        Number of moles = \frac{35}{28} = 1.25moles

From the equation of the reaction:

           1 mole of N₂ produced 2 moles of NH₃

     1.25 moles of N₂ will produce 2 x 1.25 = 2.5moles of NH₃

Mass of NH₃ = Number of moles of NH₃ x molar mass of NH₃

                       = 2.5 x (14 + 3)

                       = 42.5g

Learn more:

number of moles brainly.com/question/1841136

#learnwithBrainly

4 0
3 years ago
The center of a moon of mass m is a distance D from the center of a planet of mass M. At some distance x from the center of the
Eddi Din [679]

Answer:

x = D (M/M-m) 2.41

Explanation:

a) Let's apply Newton's second law to find the summation of force, where each force is given by the law of universal gravitation

        F = g m₁m₂ / r²

        Σ F = 0

       F1- F2 = 0

       F1 = F2

We set the reference system in the body of greatest mass (M) the planet

       F1 = g m₁ M / x²

       F2 = G m1 m / (D-x)²

      G m₁ M / x² = G m₁ m / (D-x)²

      M (D-x)² = m x²

      MD² -2MD x + M x² = m x²

     x² (M-m) -2MD x + MD² = 0

We solve the second degree equation

     x = [2MD  ±√ (4M²D² - 4 (M-m) MD²)] / 2 (M-m)

     x = {2MD ± 2D √ (M² + (M-m) M)} / 2 (M-m)

     x = D {M  ±  Ra (2M²-mM)} / (M-m)

    x = D (M ± M √ (2-m/M)) / (M-m)

    x = D (M / (M-m)) (1 ±√ (2-m/M)

Let's analyze this result, the value of M-m >> 1, so if we take the negative root, the value of x would be negative, it is out of the point between the two bodies, so the correct result must be taken with the positive root

 

    x = D (M / (M-m)) (1 + √2)

     x = D (M/M-m) 2.41

b) X = 2/3 D

     x = D (M/M-m) 2.41

     2/3 D = D (M/(M-m)) 2.41

     2/3 (M-m) = M 2.41

     2/3 M - 2/3 m = 2.41 M

     1.743 M = 0.667 m

     M/m = 0.667/1.743

     M/m =  0.38

3 0
3 years ago
How does a green leaf appear in red light? Use what you know about reflection and absorption of light.
Scilla [17]
I think the answer is Black.  Hope this helps

6 0
3 years ago
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