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3 years ago

What is the first step in allopatric speciation?

Physics

1 answer:

fomenos3 years ago

3 0

Answer:

The word Allopatric is derived from the Greek words allos = other and Patris = fatherland. Allopatric specification happens when the biological population of the same specie got separated from one another such that it stopped their gene flow or gene migration. It happens due to the geographical changes such as the movement of continents, changes in glaciers, mountains or oceans and it could be happened because of human activities like agriculture and industrial development etc. The first step of Allopatric specification is Geographical isolation. The species got separated and the long distances makes them unable to interbreed.

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If a runner has a speed of 8.66m/s and runs for 46.2s what distance is covered? tv = d

kati45 [8]

Answer:

$\text{Using the formula: }v=\frac{d}{t}\\\therefore vt=d\\\text{Plug and chug:}46.2(8.66)=400.092\text{ metres}$

6 0

2 years ago

An 84.0 kg sprinter starts a race with an acceleration of 1.76 m/s2. If the sprinter accelerates at that rate for 11 m, and then

gulaghasi [49]

Answer:

t=17.838s

Explanation:

The displacement is divided in two sections, the first is a section with constant acceleration, and the second one with constant velocity. Let's consider the first:

The acceleration is, by definition:

$a=\frac{dv}{dt}=1.76$

So, the velocity can be obtained by integrating this expression:

$v=1.76t$

The velocity is, by definition: $v=\frac{dx}{dt}$ , so

$dx=1.76tdt\\x=1.76\frac{t^{2}}{2}$ .

Do x=11 in order to find the time spent.

$11=1.76\frac{t^2}{2}\\ t^2=\frac{2*11}{76} \\t=\sqrt{12.5}=3.5355s$

At this time the velocity is: $v=1.76t=1.76*3.5355s=6.2225\frac{m}{s}$

This velocity remains constant in the section 2, so for that section the movement equation is:

$x=v*t\\t=\frac{x}{v}$

The left distance is 89 meters, and the velocity is $6.2225\frac{m}{s}$ , so:

$t=\frac{89}{6.2225}=14.303s$

So, the total time is 14.303+3.5355s=17.838s

7 0

3 years ago

in a cricket match there are 5000 spectators counted 10 by 10 the number of significant figure in the measurement will be

BabaBlast [244]

Answer:

$\boxed{3 \ Significant \ figures}$

Explanation:

Total spectators = 5000

Counted by the groups of ten, So at last the result will be:

=> 5000/10 = 500

Significant figures in 500 are 3

8 0

3 years ago

When an object travels a large distance in a small amount of time, the object's speed is

Kisachek [45]

If I were to go from the United States to China in one second, that's a large distance in an incredibly short time. I'd say that's pretty fast.

If I were to go from my room to the door of my room in a year, then that would be unbearably slow.

8 0

3 years ago

Can anyone tell me the ans of this question with steps of the solution

gavmur [86]

Answer:

Explanation:

100s:160 paces

50s: 80 paces

80*0.80= 64

3 0

3 years ago

Read 2 more answers