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Ne4ueva [31]
2 years ago
15

He radius r of a circle is increasing at a rate of 6 centimeters per minute. find the rate of change of the area when r = 35 cen

timeters. cm2/min
Mathematics
1 answer:
sergij07 [2.7K]2 years ago
3 0
You can solve this problem by following the steps below:

 1. You need the formula for calculate the area of a circle, which is:

 A=πr²

 "A" is the area of the circle
 "r" is the radius of the circle (r=35 centimeters).

 2. Now, you must take the derivative. Then, the rate of change of the area is:

 dA/dt=(2πr)(dr/dt)

 3. The radius of change of the radius "r" with respect to time, is:

 dr/dt=6 cm/min

 4. Then, you have:

 dA/dt=(2πr)(dr/dt)
 dA/dt=2π(35 cm)(6 cm/min)
 dA/dt=420π cm²/min
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\bf \begin{array}{ccll}
lawn&hours\\
\text{\textemdash\textemdash\textemdash}&\text{\textemdash\textemdash\textemdash}\\
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\end{array}\implies \cfrac{\quad \frac{1}{15}\quad }{\frac{15}{15}}=\cfrac{\quad \frac{1}{3}\quad }{h}\implies \cfrac{1}{15}\cdot \cfrac{15}{15}=\cfrac{\quad \frac{1}{3}\quad }{\frac{h}{1}}
\\\\\\
\cfrac{1}{15}=\cfrac{1}{3}\cdot \cfrac{1}{h}\implies \cfrac{1}{15}=\cfrac{1}{3h}\implies 3h=15\implies h=\cfrac{15}{3}\implies h=5
6 0
2 years ago
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Can you answer this one for my plz I need before Monday ty
ira [324]
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.. -x^2 -4x +1
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3 years ago
A particular chemistry book costs $6 less than a particular physics book, while two such chemistry books and three such physics
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Answer:

Step-by-step explanation:

Let's say the Physics book costs $x

The Chemistry book will cost $x - $6

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$5x = $111

x = $22\frac{1}{5}

So the Physics book costs;  $22\frac{1}{5}

and the Chemistry book costs  $22\frac{1}{5} - 6 =  $16\frac{1}{5}

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