Question

A 1500 kg truck is acted upon by a force that decreases its speed from 25 m/s to 15 m/s in 8 s. What is the magnitude of the force acting on the truck?

Answer 1

Answer:

F = 1,875 N

Explanation:

force=

$\frac{change \: in \: momentum}{time \: taken}$

∆H = m∆V

where ∆H ----> change in momentum.

( final momentum - initial momentum )

and ∆V ----> change in velocity

( final velocity - initial velocity )

and m ----> is mass

then f =

$\frac{1500 \times (25 - 15)}{8}$

= 1,875 N