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2 years ago

I traveled 6.00 km to school in 0.250 hours . What was my average speed

Physics

1 answer:

SOVA2 [1]2 years ago

5 0

Answer: 6.67 m/s

Explanation:

Recall that average speed is the total distance covered by a moving body divided by the total time taken. The SI unit is metres per second.

i.e Average speed = distance/time taken

Given that:

Distance covered = 6.00 km

Convert kilometers to meters

If 1 km = 1000 m

6.00 km = (6.00 x 1000) = 6000m

Time taken to school = 0.250 hours

Convert time in hours to seconds

If 1 hour = 60 minutes & 1 minute = 60 seconds

Then, 0.250 hours = (0.250 x 60 x 60)

= 900 seconds

Average speed = ?

Average speed = 6000m/900s

= 6.67 m/s

Thus, your average speed to school is 6.67 m/s

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A 70.0 kg man jumping from a window lands in an elevated fire rescue net 11.0 m below the window. He momentarily stops when he h

levacccp [35]

Answer:

70.15 Joule

Explanation:

mass of man, m = 70 kg

intial length, l = 11 m

extension, Δl = 1.5 m

Let K is the spring constant.

In the equilibrium position

mg = K l

70 x 9.8 = K x 11

K = 62.36 N/m

Potential energy stored, U = 0.5 x K x Δl²

U = 0.5 x 62.36 x 1.5 x 1.5

U = 70.15 Joule

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2 years ago

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2 years ago

A young man exerted a force of 9000N on a stalled car but was unable to move it. How much work was done?

rodikova [14]

Answer:

No work was done at all.

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3 years ago

How to find a planet’s gravitational field strength using its radius?

grin007 [14]

The gravitational field strength is approximately equal to 10 N.

<u>Explanation:</u>

Gravitational field strength is the measure of gravitational force acting on any object placed on the surface of the planet. Generally, the mass of the object is considered as 1 kg.

So the gravitational field strength will be equal to the gravitational force acting on the object.

The formula for gravitational field strength is

$g = \frac{F}{m}$

Here g is the gravitational field strength, m is the mass of the object placed on the surface and F is the gravitational force acting on the object.

Since, the mass of any object placed on the surface of earth will be negligible compared to the mass of Earth, so the mass of the object is considered as 1 kg.

Then the g = F

And $F =\frac{GMm}{r^{2} }$

Here G is the gravitational constant, M is the mass of Earth and m is the mass of the object placed on the surface, while r is the radius of the Earth.

$g = F = \frac{6 \times 10^{24} \times 6.67 \times 10^{-11} \times 1}{(6.6 \times 10^{6}) ^{2} }$

$g = 0.977 \times 10^1= 9.77\ N$

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2 years ago

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VMariaS [17]

At point C because it is at the lowest position.

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2 years ago