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grin007 [14]
2 years ago
9

11. A collection of a small group of factors that are related is known as a(n)

Physics
1 answer:
malfutka [58]2 years ago
5 0

Answer:

system

Explanation:

they are all put together as one, and they are a group

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P2o3 is <span>diphosphorus trioxide.
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According to the rayleigh criterion, what is the shortest object we could resolve at the 25.0 cm near point with light of wavele
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Answer:

6.71 *10^{-5} rad

Explanation:

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The minimum resolvable angle = 6.71 *10^{-5} rad

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The distance from the Earth to the Sun equals 1 AU. Neptune is 30 AU from the Sun. How far is Neptune from the Earth?AU
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Answer:

Depending on the relative position of the Earth the Sun and Neptune in the Earths orbit the distances are;

The closest (minimum) distance of Neptune from the Earth is 29 AU

The farthest (maximum) distance of Neptune fro the Earth is 31 AU

Explanation:

The following parameters are given;

The distance from the Earth to the Sun = 1 AU

The distance of Neptune from the Earth = 30 AU

We have;

When the Sun is between the Earth and Neptune, the distance is found by the relation;

Distance from the Earth to Neptune = 30 + 1 = 31 AU

When the Earth is between the Sun  and Neptune, the distance is found by the relation;

Distance from the Earth to Neptune = 30 - 1 = 29 AU

Therefore, the closest distance from Neptune to the Earth in the Earth's Orbit is 29 AU

The farthest distance from Neptune to the Earth in the Earth's orbit is 31 AU.

8 0
3 years ago
In a thundercloud there may be an electric charge of +40 C near the top of the cloud and -40 C near the bottom of the cloud. The
Ratling [72]

Answer:

Electric force, F=-3.59\times 10^6\ N

Explanation:

Given that,

Electric charge 1, q_1=+40\ C

Electric charge 2, q_2=-40\ C

Distance, d=2\ km=2\times 10^3\ m

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The electric force between these two sets of charges.

Solution,

There exists a force between two electric charges and this force is called electrostatic force. It is equal to the product of electric charged divided by square of distance between them.

F=k\dfrac{q_1q_2}{d^2}

k is the electrostatic constant

F=8.99\times 10^9\times \dfrac{40\times (-40)}{(2\times 10^3)^2}

F=-3.59\times 10^6\ N

So, the electric force between these two sets of charges is -3.59\times 10^6\ N.

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