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AleksandrR [38]
3 years ago
15

After an incandescent lamp is turned on, the temperature of its filament rapidly increases from room temperature to its operatin

g temperature. As the temperature of the filament increases, what happens to the resistance of the filament and the current through the filament?
(1) The resistance increases and the current decreases.
(2) The resistance increases and the current increases.
(3) The resistance decreases and the current decreases.
(4) The resistance decreases and the current increases
Physics
2 answers:
Strike441 [17]3 years ago
8 0
I think the correct answer from the choices listed above is option 1. As the temperature of the filament increases, the resistance of the filament and the current through the filament would be that the <span> resistance increases and the current decreases. Hope this answers the question.</span>
IrinaVladis [17]3 years ago
6 0

Answer: (1) The resistance increases and the current decreases.

Explanation:  

When the temperature of the filament increases, the vibrational energy of the constituent atoms increases which leads to increase in inter-atomic collision. Thus, the resistance would increase. The increases in resistance would obstruct the flow of charges more leading to decrease in the value of the current.

Hence, when the temperature of the filament increase, the resistance increases and current decreases.

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In cats, short hair is dominant and long hair is recessive. If a cat has the genotype of hh, what type of hair will it have?
raketka [301]

Answer:

long hair

Explanation:

long hair = hh

short hair= HH

and medium= Hh

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3 years ago
You get home on a cold winter day and turn on the hea
Allushta [10]

The heat transferred by room heater to the room is an example of convection heat flow.

Answer: Option D

<u>Explanation:</u>

It is known that heat or thermal energy generally flows from high temperature to low temperature. Heat can be transferred in four ways. They are conduction, convection, radiation and electro-magnetic waves. So, in the present case, if we are turning on the heater highers the temperature of the room, we need to use room heaters. And generally room heaters utilize convection technology to flow the heat energy.

In convection mode of heat flow, the heat energy generated at the source i.e., in the coils of the room heater is made to flow away from the source using the fan or radiator kind of thing. So, this process of transfer of heat energy from the point of generation by making the heat flow or rise is termed as convection. And thus, convection is the best example which is used in room heater.

4 0
4 years ago
An emf source with emf of 200 V, a resistor with R =50.0 Ω, and a capacitor with C = 4.0 mF are connected in series. As the capa
Gemiola [76]

Answer:

0.6 C

Explanation:

From the question,

Since the Resistor and the capacitor are connected in series.

The voltage across the resistor + Voltage across the capacitor = Total voltage.

Vt = Vr+Vc............... Equation 1

Where Vt = Total voltage, Vr = Voltage across the resistor, Vc = Voltage across the capacitor

make Vc the subject of the equation

Vc = Vt-Vr.............. Equation 2

From ohm's law,

Vr = IR................... equation 3

Where I = current, R = Resistance.

Given: I = 1 A, R = 50 Ω

Substitute into equation 3

Vr = 1(50)

Vr = 50 V

Also given: Vt = 200 V

Substitute into equation 2

Vc = 200-50

Vc = 150 V.

Applying,

Q = CVc..................... Equation 4

Where Q = charge on each plate of the capacitor, C = Capacitance of the capacitor

Given: C = 4.0 mF = 4.0×10⁻³ F, Vc = 150 V

Substitute into equation 4

Q = 4.0×10⁻³(150)

Q = 0.6 C

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3 years ago
Please help I'm having a mental breakdown
galina1969 [7]

Answer:

there it is fella

And that's according to ma observation

4 0
3 years ago
A bag is dropped from a balloon that is 50m above the ground and rising at 15m/s. calculate
ANTONII [103]

Answer:

See the answers below

Explanation:

We can solve this problem using the principle of energy conservation. That is, the energy is conserved before and after dropping the bag.

For this case we have mechanical energy, which is the sum of the kinetic and potential energies.

E_{1}=E_{2}

where:

E_{1}=E_{k}+E_{p}\\E_{2}=E_{p}

Ek = kinetic energy [J] (units of Joules)

Ep = potential energy [J]

In the final Energy (2), there is only potential energy. since when the balloon reaches the maximum height its velocity is zero, that is, there is no kinetic energy.

A)

m*g*h+\frac{1}{2}*m*v^{2} =m*g*h_{1} \\9.81*50+0.5*(15)^{2}=9.81*h_{1}\\h_{1} = 61.46 [m]

B)

With the value calculated above we can find the acceleration of the balloon.

The distance traveled is the difference between the maximum height and 50 meters.

x = 61.46-50\\x = 11.46[m]

With the following equation of kinematics.

v_{f}^{2} =v_{o}^{2}+2*a*x

0 = 15^{2} +2*a*11.46\\a = - 9.816 [m/s^{2} ]

The negative sign indicates that the acceleration acts downward. That is, in the opposite direction to the movement.

We can use the following equation of kinematics to find the final velocity after 4 seconds.

v_{f}=v_{o}-a*t\\v_{f}=15-9.816*(4)\\v_{f}=-24.24 [m/s]

Now the distance:

v_{f}^{2} =v_{o}^{2}-2*a*x\\(24.24)^{2} =(15)^{2} -2*9.81*x\\x = 18.48 [m]\\x_{f}=50+18.48 = 68.48 [m]

c) Using the following equation of kinematics.

v_{f}=v_{o}-a*t\\0 = 15-9.81*t\\15=9.81*t\\t = 1.52 [s]

4 0
3 years ago
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