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3 years ago

HELP ASAP

Physics

1 answer:

labwork [276]3 years ago

6 0

Answer:

Explanation:

A is summer, C is winter, B should be fall in-between those 2

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Total momentum before a collision is equal to total momentum after a collision.what does this define

otez555 [7]

Answer:haha

Explanation:dont know

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3 years ago

A 4.0 Ω resistor has a current of 3.0 A in it for 5.0 min. How many electrons pass 3. through the resistor during this time inte

musickatia [10]

Answer:

Number of electrons, $n=5.62\times 10^{21}$

Explanation:

It is given that,

Resistance, R = 4 ohms

Current, I = 3 A

Time, t = 5 min = 300 s

We need to find the number of electrons pass through the resistor during this time interval. Let the number of electron is n.

i.e. q = n e ...............(1)

And current, $I=\dfrac{q}{t}$

$I\times t=n\times e$

$n=\dfrac{It}{e}$

e is the charge of an electron

$n=\dfrac{3\ A\times 300\ s}{1.6\times 10^{-19}}$

$n=5.62\times 10^{21}$

So, the number of electrons pass through the resistor is $5.62\times 10^{21}$ . Hence, this is the required solution.

6 0

3 years ago

Which one of the following distances is the shortest?

Kitty [74]

I think the correct answer is C

6 0

3 years ago

A ball is kicked from the top of a building with a velocity of 50 m/s and lands 165 m away from the base of the buildi

solniwko [45]

Answer:

32.3 m/s

Explanation:

The ball follows a projectile motion, where:

- The horizontal motion is a uniform motion at costant speed

- The vertical motion is a free fall motion (constant acceleration)

We start by analyzing the horizontal motion. The ball travels horizontally at constant speed of

$v_x = 50 m/s$

and it covers a distance of

d = 165 m

So, the total time of flight of the ball is

$t=\frac{d}{v_x}=\frac{165}{50}=3.3 s$

In order to find the vertical velocity of the ball, we have now to analyze its vertical motion.

The vertical motion is a free-fall motion, so the ball is falling at constant acceleration; therefore we can use the following suvat equation:

$v_y = u_y +at$

where

$v_y$ is the vertical velocity at time t

$u_y=0$ is the initial vertical velocity

$a=g=9.8 m/s^2$ is the acceleration of gravity (taking downward as positive direction)

Substituting t = 3.3 s (the time of flight), we find the final vertical velocity of the ball:

$v=0 + (9.8)(3.3)=32.3 m/s$

5 0

4 years ago

During a blackout, you are trapped in a tall building. you want to call rescuers on your cell phone, but you can't remember whic

Gennadij [26K]

Let the height where we are trapped is H

now to find the time to reach the key at the bottom is given as

$y = v_i t + \frac{1}{2}at^2$

now we have

$H = \frac{1}{2}gt^2$

$t = \sqrt{\frac{2H}{g}}$

now if the speed of sound is considered to be 340 m/s then time taken by the sound to reach at the top is given as

$t = \frac{H}{340}$

now the total time is given as

$\sqrt{\frac{2H}{g}} + \frac{H}{340} = 3.27$

now by solving above equation we have

H = 48 m

now height of one floor is 3 m

so our position must be

$N = \frac{48}{3} = 16 th \:floor$

3 0

3 years ago