Explanation:
Effective communication with patients will enable one to know the needs of the patient better as well as reducing the barriers to understanding each other for both parties.
To be an effective communicator while educating patients, the person must:
- It is important to establish good rapport with the patient. By so doing they can trust you and let you in. Show empathy. Do not make them feel like you are judging them
- Use proper body language. Make eye contacts and try to be on the same level as the patient so you can be face to face with them.
- make the interaction easier for them. You have to keep questions as well as your sentences short and moderate. Stay on topic and always make sure that concepts are clear to them.
- show respect. try not to speak with commands. Give the patient opportunity to make choices.
- be patient with them. Due to age or the nature of their illnesses, the patient may be slow in speech or movement. help them to move at their own pace by not rushing them.
- give them time to respond and ask questions. this will make communication more effective.
- you cause graphics where necessary or written instructions for the patient.
Quantity of electrical charge is measured in Coulombs.
The symbol is C.
b. C
It is same as calculating maths for math
Answer:
T = 1633N
Explanation:
The weight of the man is given by m×g =112×9.8= 1097.6N
Coefficient of Kinetic Friction = frictional force / Normal reaction ( Weight of object)
The coefficient of Kinetic Friction= Tan A
Where A is the angle of inclination
The angle of inclination is Tan^-1{0.876} = 41.21°
By identity sin A = Opposite( weight)/ hypothenus ( Tension)
Hence the tension is T = 1097.6/sin 41.21 =
T = 1633N
Answer:
The magnitude of the car's acceleration as it slows during braking is 36.81 m/s²
Explanation:
From the question, the given values are as follows:
Initial velocity, u = 90 m/s
final velocity, v = 0 m/s
distance, s = 110 m
acceleration, a = ?
Using the equation of motion, v² = u² + 2as
(90)² + 2 * 110 * a = 0
8100 + 220a = 0
220a = -8100
a = -8100/220
a = -36.81 m/s²
The value for acceleration is negative showing that car is decelerating to a stop. The magnitude of the car's acceleration as it slows during braking is therefore 36.81 m/s²
