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WINSTONCH [101]
3 years ago
12

Does the mass change how a bouncy ball bounce

Physics
1 answer:
Snowcat [4.5K]3 years ago
6 0
Mass affects a ball's bounce through kinetic energy. The more mass an object has, the more kinetic energy it has when dropped, due to gravity. How much the ball deforms is based on its chemical makeup, or in this case, elasticity. When the ball deforms, the kinetic energy is converted into potential energy. As many kinds of balls have high amounts of elasticity, the potential energy converts back to kinetic energy when the deformation of the ball returns to its normal state. If the force of impact is too great for the ball to absorb, it may collapse and lose its bounce as the energy is dissipated in a different manner.
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What is the primary way that a metamorphic rock form
Virty [35]
Metamorphic rocks form from the alteration of other rocks through pressure and temperature induced changes in the minerals.
5 0
3 years ago
Many medicines started out as natural products. Aspirin was originally made from _______________
balu736 [363]
The answer will most definitely be D
4 0
2 years ago
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Imagine a raindrop starting from rest in a cloud 2 km in the air. If it fell with no air friction at all, it would accelerate to
LenKa [72]

Answer:

2) 433 mph

Explanation:

The final velocity of the raindrop as it reaches the ground can be found by using the equation for a uniformly accelerated motion:

v^2 = u^2 + 2ad

where

v is the final velocity

u = 0 is the initial velocity (the raindrop starts from rest)

a = g = 9.8 m/s^2 is the acceleration due to gravity

d = 2 km = 2000 m is the distance covered

Solving for v,

v=\sqrt{u^2 +2gd}=\sqrt{0^2+2(9.8 m/s^2)(2000)}=198 m/s

And keeping in mind that

1 mile = 1609 metres

1 hour = 3600 s

The speed converted into miles per hour is

v=198 \frac{m}{s}\cdot \frac{3600 s/h}{1609 m/mi}=433 mph

5 0
3 years ago
Venus has an average distance to the sun of 0.723 AU. In two or more complete sentences, explain how to calculate the orbital pe
Mice21 [21]

As per the question the distance of venus from sun is given as 0.723 AU

We have been asked to calculate the time period of the planet venus.

As per kepler's laws of planetary motion the square of time period of planet is directly proportional to the cube of semi major axis. mathematically

                                        T^{2} \alpha R^{3}

                                         ⇒ T^{2} = KR^{3} where is k is the proportionality  constant

We may solve this problem by comparing with the time period of the earth . We know that time period of earth is 365.5 days

Hence T_{1} =365.5 days

The distance of sun from earth is taken as 1 AU i.e the mean distance of earth from sun

Hence R_{1} =1 AU

The distance of venus from sun is 0.723 AU i.eR_{2} =0.723

From keplers law we know that-\frac{T_{1} ^{2} }{T_{2} ^{2} } =\frac{R_{1} ^{3} }{R_{2} ^{3} }

                            ⇒T_{2} ^{2} =T_{1} ^{2} *\frac{R_{2} ^{3} }{R_{1} ^{3} }

Putting the values mentioned above we get-

                                      T_{2} ^{2} =50,350.132851075

                                         ⇒ T_{2} =\sqrt{50,350.132851075}

                                        ⇒T_{2} = 224.388352752710 days.

Hence the time period of venus is 224.388352752710 days

                                         

                     






                           

7 0
4 years ago
Read 2 more answers
What fundamental frequency would you expect from blowing across the top of an empty soda bottle that is 24 cm deep
kari74 [83]

Answer:

708.3 Hz

Explanation:

For an open-air column, like the empty can, the fundamental frequency is given by

f_1 = \frac{v}{2L}

where

v = 340 m/s is the speed of sound

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In this problem, the length of the bottle is

L = 24 cm = 0.24 m

Therefore, the fundamental frequency is

f_1 = \frac{340 m/s}{2(0.24 m)}=708.3 Hz

8 0
3 years ago
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