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3 years ago

A 2300 kg sailboat is moving west at 5.5 m/s when an eastward wind

1 answer:

5 0

The boat is initially at equilibrium since it seems to start off at a constant speed of 5.5 m/s. If the wind applies a force of 950 N, then it is applying an acceleration a of

950 N = (2300 kg) a

a = (950 N) / (2300 kg)

a ≈ 0.413 m/s²

Take east to be positive and west to be negative, so that the boat has an initial velocity of -5.5 m/s. Then after 11.5 s, the boat will attain a velocity of

v = -5.5 m/s + a (11.5 s)

v = -0.75 m/s

which means the wind slows the boat down to a velocity of 0.75 m/s westward.

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How far from the base of the platform does she land?

seropon [69]

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She's in the air for 1.1 second before she hits the water.

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3 years ago

Calculate the mass (in SI units) of (a) a 160 lb human being; (b) a 1.9 lb cockatoo. Calculate the weight (in English units) of

kondaur [170]

Explanation:

1. Force applied on an object is given by :

F = W = mg

(a) A 160 lb human being, F = 160 lb

g = acceleration due to gravity, g = 32 ft/s²

$m=\dfrac{F}{g}$

$m=\dfrac{160\ lb}{32\ ft/s^2}$

m = 5 kg

(b) A 1.9 lb cockatoo, F = 1.9 lb

$m=\dfrac{F}{g}$

$m=\dfrac{1.9\ lb}{32\ ft/s^2}$

m = 0.059 kg

2. (a) A 2300 kg rhinoceros, m = 2300 kg

$W=2300\ kg\times 32\ ft/s^2=73600\ lb$

(b) A 22 g song sparrow, m = 22 g = 0.022 kg

$W=0.022\ kg\times 32\ ft/s^2=0.704\ lb$

Hence, this is the required solution.

5 0

3 years ago

Please answer all of these questions and you will get the brain list

pogonyaev

Answer:

1=900j

2=140j

3=5m

Explanation:

work=force×displacement

w=450×2

w=900j

w=f×s

w=70×2

w=140j

w=f×s

200=40×s

200/40=s

s=5m

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3 years ago

A tennis ball is dropped from a height of 1.21m above the ground. Calculate its velocity when it is 0.27m from the ground.

wlad13 [49]

9.81m/s^2 x .27 = 2.6487m/s

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3 years ago

Which of the following statements is true of the strong nuclear force?

vredina [299]

Explanation:

it holds protons and neutrons together

5 0

3 years ago