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3 years ago

Solve the Linear system using substitution X=6-4y 3x-2y=1

1 answer:

5 0

3(6-4y)-2y=1
18-12y-2y=1
18-14y=1
-14y=-17
Y=17/14
Now with a calculator plug in 17/4 multiply it by 4 and subtract the solution from 6 and h get x

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Someone help please struggling on this answer thank you so much!

mestny [16]

Answer:

-x+8=6

Step-by-step explanation:

x+5-1(2x)+(-1)(-3)=6

x+5-1-2x+3=6

ans (-x+8=6)

x+8

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3 years ago

Is 7/11 a irrational number

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Answer: No, it’s rational number

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4 years ago

Read 2 more answers

How many terms are in (3x^2-3)(3x^2+3)

Marta_Voda [28]

The number of terms in the expression given is; 2.

<h3>How many term are in the expression given?</h3>

It follows from the task content that the expression given is; (3x^2-3)(3x^2+3).

It therefore follows the converse of law regarding difference of two squares that the expression given can be rewritten as;

= 9x⁴ -9

Read more on difference of two squares;

brainly.com/question/3189867

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2 years ago

Assume that you have a large sample of radioactive atoms, arranged in a rectangular lattice. Imagine that this lattice has some

babunello [35]

Answer:

I dont care

Step-by-step explanation:

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3 years ago

Please answer both questions math

djyliett [7]

Answer:

$3$ and perpendicular

Step-by-step explanation:

It's important to remember that equations of lines are always set up in the format of $y=mx+c$ .

$y$ is the $y$ value, $m$ is the gradient/slope, $x$ is the $x$ value and $c$ is the y-intercept.

Therefore, we must always rearrange our line equations so that $y$ is the subject.

In the first question, we are given the equation $2x+6y=12$ .

We rearrange to make $y$ the subject:

$6y = 12-2x$

Then, we divide both sides by 6 to have the $y$ isolated:

$\frac{6}{6} y = \frac{12}{6} - \frac{2}{6}x\\\\ y = 2 - \frac{1}{3}x$

To find a perpendicular slope, we use the negative reciprocal of the original slope. The negative part of that means we negate the value (it becomes inverse) and the reciprocal part means that we flip the fraction.

So here, the slope is $-\frac{1}{3}$ .

So, the negative reciprocal of that would be $3$ because we inverse the sign (the negative becomes positive) and the fraction is flipped to create $\frac{3}{1}=3$ .

So, the perpendicular slope is $3$ .

In the second question, we have two equations. They both need to be rearranged to isolate the $y$ .

$4x-y=5\\4x = 5 + y\\y = 4x - 5\\\\4y = -x-12\\y = -\frac{1}{4}x - 3$

Look at the slopes of the two equations. If you look carefully, you will see that they are inverse of each other (one is positive and one is negative) and if you imagine $4 = \frac{4}{1}$ , the fraction is flipped.

This means that the values are negative reciprocals of each other, meaning the lines are perpendicular.

5 0

2 years ago