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Margaret [11]
3 years ago
9

Fish are able to acquire the oxygen needed for respiration under water using gills. This is an example of which type of adaptati

on?
Physics
1 answer:
stiks02 [169]3 years ago
3 0

Answer:

Structural

Explanation:

Structural adaptations are a change to a organism's body, gills are part of the fish's body which would be why this is a structural adaptation!

Hope this helped! Stay safe have a good day or night!

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at a temperature of 10 c,700 ml of hydrogen is collected. if this gas is put into a 1000 ml container what will its new temperat
erastovalidia [21]

Answer:

14.3°C

Explanation:

Find the ratio of 10°C : 700ml then use the same ratio to 1000ml.

Have a great day <3

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2 years ago
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1.)Two objects, one of m=20,000 kg, and another of 12,500 kg, are placed at a distance of 5 meters apart. What is the force of g
Delvig [45]

1) 6.67\cdot 10^{-4} N

The force of gravitation between the two objects is given by:

F=G\frac{m_1 m_2}{r^2}

where

G=6.67\cdot 10^{-11} kg^{-1} m^{3} s^{-2} is the gravitational constant

m1 = 20,000 kg is the mass of the first object

m2 = 12,500 kg is the mass of the second object

r = 5 m is the distance between the two objects

Substituting the numbers inside the equation, we find

F=(6.67\cdot 10^{-11})\frac{(20,000 kg)(12,500 kg)}{(5 m)^2}=6.67\cdot 10^{-4} N


2)  2.7\cdot 10^{-3} N

From the formula in exercise 1), we see that the force is inversely proportional to the square of the distance:

F \sim \frac{1}{r^2}

this means that if we cut in a half the distance without changing the masses, the magnitude of the forces changes by a factor

F'\sim \frac{1}{(r/2)^2}=4 \frac{1}{r^2}=4F

So, the gravitational force increases by a factor 4. Therefore, the new force will be

F' = 4 F=4(6.67\cdot 10^{-4} N)=2.7\cdot 10^{-3} N


3)  12.5 Nm

The torque is equal to the product between the magnitude of the perpendicular force and the distance between the point of application of the force and the centre of rotation:

\tau=Fd

Where, in this case:

F = 25 N is the perpendicular force

d = 0.5 m is the distance between the force and the center

By using the equation, we find

\tau=(25 N)(0.5 m)=12.5 Nm


4) 0.049 kg m^2/s

The relationship between angular momentum (L), moment of inertia (I) and angular velocity (\omega) is:

L=I\omega

In this problem, we have

I=0.007875 kgm^2

\omega=6.28 rad/s

So, the angular momentum is

L=I\omega=(0.007875 kgm^2)(6.28 rad/s)=0.049 kg m^2/s

6 0
2 years ago
The relationship among speed, distance, and time is
alexdok [17]
Distance= speed (multiplied by) time
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Suppose a ball of putty moving horizontally with 1kg.m/s of momentum collides and sticks to an identical ball of puffy moving ve
WARRIOR [948]

Answer:

Vector sum of two vectors at right angles

p={p₁²+p₂²} =2 =1.41 kg•m/s

Explanation:

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3 years ago
Why is the temperature usually warmest a the equator and colder as you move towards the poles? *
Gwar [14]

Answer:

Option D, The equator gets more direct sunlight throughout the yea

Explanation:

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