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3 years ago

What do you use to light a laboratory burner

Physics

2 answers:

Hunter-Best [27]3 years ago

6 0

A needle valve and collar.

Yuliya22 [10]3 years ago

5 0

The lab burner may be one that burns alcohol or natural gas. In either case, when you're ready to heat something and need to light the burner, a match will do a fine job.

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3. The coefficient of kinetic friction between an object and the surface upon which it is sliding is

Neporo4naja [7]

Answer:

Explanation:

8 0

3 years ago

If there are no other changes, explain what effect reducing the mass of the car will have on its acceleration when starting to m

densk [106]

Answer:

when the mass of an object is decreased, the acceleration will increase

when mass is increased, acceleration decreases

3 0

3 years ago

The distance between the first and fifth minima of a single-slit diffraction pattern is 0.500 mm with the screen 37.0 cm away fr

WARRIOR [948]

In the single-slit experiment, the displacement of the minima of the diffraction pattern on the screen is given by
$y_n= \frac{n \lambda D}{a}$ (1)
where
n is the order of the minimum
y is the displacement of the nth-minimum from the center of the diffraction pattern
$\lambda$ is the light's wavelength
D is the distance of the screen from the slit
a is the width of the slit

In our problem,
$D=37.0 cm=0.37 m$
$\lambda=530 nm=5.3 \cdot 10^{-7} m$
while the distance between the first and the fifth minima is
$y_5-y_1 = 0.500 mm=0.5 \cdot 10^{-3} m$ (2)

If we use the formula to rewrite $y_5, y_1$ , eq.(2) becomes
$\frac{5 \lambda D}{a} - \frac{1 \lambda D}{a} =\frac{4 \lambda D}{a}= 0.5 \cdot 10^{-3} m$
Which we can solve to find a, the width of the slit:
$a= \frac{4 \lambda D}{0.5 \cdot 10^{-3} m}= \frac{4 (5.3 \cdot 10^{-7} m)(0.37 m)}{0.5 \cdot 10^{-3} m}= 1.57 \cdot 10^{-3} m=1.57 mm$

7 0

4 years ago

Potential energy

AnnZ [28]

The answer would be B.

7 0

3 years ago

What is the period of a pendulum that takes 3 seconds to move forward, and another 3 seconds to come back?

Serga [27]

The period of the pendulum is 6 seconds.

<h3>What is period?</h3>

Period is the time taken for a simple pendulum to move to(forward) and fro(backward). The s.i unit of period is seconds(s).

Note: When a simple pendulum moves to and fro. it completes one cycle.

From the question, The period of the pendulum is calculated using the formula below.

<h3>Formula</h3>

T = a+b.............. Equation 1

Where:

T = Period of the pendulum
a = Time taken for the pendulum to move forward
b = Time taken for the pendulum to move backward.

From the question,

Given:

a = 3 seconds
b = seconds

Substitute the values above into equation 1

T = 3+3
T = 6 seconds.

Hence, The period of the pendulum is 6 seconds.

Learn more about period here: brainly.com/question/21924087

5 0

3 years ago