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Vladimir79 [104]
3 years ago
12

What would be the mass of an object that is moving at 5 m/s, with a total momentum of 1500 kg*m/s southeast?

Physics
1 answer:
USPshnik [31]3 years ago
7 0

Answer:

The mass of the object is 300 kg

Explanation:

The given parameters are;

The velocity of the object = 5 m/s southeast

The total momentum of the object = 1500 kg·m/s

The equation for linear momentum, is given as follows;

Momentum = Mass × Velocity

Therefore, the mass of the object can be found as follows;

The \ mass \ of \ the  \ object= \dfrac{The \ momentum \ of \ the  \ object}{The \ velocity  \ of \ the  \ object}

Therefore, we have;

The \ mass \ of \ the  \ object= \dfrac{1500 \ kg \cdot m/s}{5 \ m/s} = 300 \ kg

The mass of the object = 300 kg.

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Vesna [10]

Complete Question

A football coach walks 18 meters westward, then 12 meters eastward, then 28 meters westward, and finally 14 meters eastward.

a

From this motion what is the distance covered

b

What is the magnitude and direction of the displacement

Answer:

a

  D =   72 \  m

b

Magnitude

             d =  - 20 \ m

 Direction  

West

Explanation:

From the question we are told that

The first distance covered westward is d_w_1  =  18 \  m /tex]     The  first distance covered eastward is [tex]d_e1 =  12 \  m /tex]      The second distance covered westward is [tex]d_w_2  =  28 \  m /tex]      The  second distance covered eastward is [tex]d_e2 =  14 \  m /tex]   Generally the distance covered is mathematically represented as       [tex]D =  d_w1 + d_w2 + d_e1 + d_e2

=> D =   18 + 28 + 12 +  14

=> D =   72 \  m

For the second question eastward is in the direction of the positive x-axis so it would be positive and westward is in the direction of the negative x-axis so it would be negative

The magnitude of the displacement is

d =  -d_w1 -d_w2 + d_e1 + d_e2

=>  d =  -18-28 + 12 + 14

=> d =  - 20 \ m

The direction is west

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3 years ago
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Answer:

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A theory was not originally a hypothesis. true or false?
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False.

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A weather balloon is partially inflated with helium gas to a volume of 2.0 m³. The pressure was measured at 101 kPa and the temp
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Answer:

4.7 m³

Explanation:

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V2 = ?

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101 × 2 / 300.15 = 40 × V2 / 283.15

V2 × 40 / 283.15 ≈ 0.67

V2 = 0.67 × 283.15 / 40

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