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Dafna11 [192]
3 years ago
12

How many significant figures are in 25.030 , 0.006 070 , 1.004 and 1.3005 20 and why ?

Physics
2 answers:
likoan [24]3 years ago
7 0

Answer:

Explanation:

The significant figures are defined as the figures that give the value and information of the accuracy of a measurement. The zero is the number that can have two behaviors if it is to the right of us numbers is significant since it gives an idea of ​​the precision of the meditation, but if it is on the left and only serves to indicate the position of the decimal point it is not significant ; All of us numbers are always significant.

 Using the above statements we will shrink the significant numbers numbers:

number  Significant     description

                figure

25.030        5                  all significant, zero right indicates measurement accuracy

0.006070    4                 zeros to the left of the “6” indicate position of the decimal point, they are not significant

1,004            4                 all significant

1.300520     7                 all significant, zero right indicates accuracy is significant

Kaylis [27]3 years ago
5 0
25.030: 5 because zeroes are after decimal

0.006: 3 because 2 zeroes are after decimal

1.004: 4 because zeroes are between numbers

(Not sure what you meant to write for these)

1.300520: 7

1.3005: 5 because zeroes are after decimal and between numbers

20: 1 because zero isn't after a decimal or between numbers

Numbers other than 0 are always SigFigs!

Hope I helped! :)
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So a Shuttle that weighed 20 million Newtons on the launch pad weighed roughly  17 million Newtons while in orbit.


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At t=0, a particle leaves the origin with a velocity of 9.0 m/s in the positive y direction and moves in the xy plane with a con
fiasKO [112]

Answer:

e.26m/s

Explanation:

Vf=Vi+at      (1)

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X= X₀+at

now, in the i direction

15=O+2t or t=7.5 when x position is 15

Lets put that into the (1) equation, solve for Vf.

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5 0
3 years ago
Help<br> A. 12,240<br> B. 6,120
nata0808 [166]

Answer:

A. 12,240.

Explanation:

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hope this helped :)

3 0
2 years ago
A positively charged wire with uniform charge density +λ lies along the x-axis and a negatively charged wire with uniform charge
Kisachek [45]

Answer:

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Explanation:

The electric field created by an infinitely long wire can be found by Gauss' Law.

\int \vec{E}d\vec{a} = \frac{Q_{enc}}{\epsilon_0}\\E2\pi r h = \frac{\lambda h}{\epsilon_0}\\\vec{E} = \frac{\lambda}{2\pi\epsilon_0 r} \^r

For the electric field at point (x,y), the superposition of electric fields created by both lines should be calculated. The distance 'r' for the first wire is equal to 'y', and equal to 'x' for the second wire.

\vec{E} = \vec{E}_1 + \vec{E}_2 = \frac{\lambda}{2\pi\epsilon_0 y}(\^y) + \frac{-\lambda}{2\pi\epsilon_0 x}(\^x)\\\vec{E} = \frac{\lambda}{2\pi\epsilon_0 y}(\^y) - \frac{\lambda}{2\pi\epsilon_0 x}(\^x)\\\vec{E} = \frac{\lambda}{2\pi\epsilon_0}[\frac{1}{y}(\^y) - \frac{1}{x}(\^x)]

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