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miv72 [106K]
3 years ago
8

The top of a vertical cylinder is sealed with a circular lid. If the cylinder is evacuated, what is the minimum force required t

o remove the lid from the top of the cylinder? The radius of the cylinder is 6.00 cm. Assume the surrounding air is at a pressure of 1 atm = 1.01 ✕ 105 Pa. Express your answer in units of newtons.
Physics
1 answer:
gladu [14]3 years ago
3 0

Answer:

F = 1142.28 N

Explanation:

It is given that,

Radius of the cylinder, r = 6 cm = 0.06 m

Pressure of the surrounding air, P=1.01\times 10^5\ Pa  

Let F the minimum force required to remove the lid from the top of the cylinder. We know that the force acting per unit area is called pressure exerted. Its formula is given by :

P=\dfrac{F}{A}

F=P\times A

F=P\times \pi r^2

F=1.01\times 10^5\ Pa\times \pi (0.06)^2

F = 1142.28 N

So, the minimum force required to remove the lid from the top of the cylinder is 1142.28 N. Hence, this is the required solution.

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Answer:

the centripetal force on the satellite in the larger orbit is _one fourth_ as that on the satellite in the smaller orbit.

Explanation:

Mass of satellite, m

orbit radius of first, r1 = r

orbit radius of second, r2  = 2r

Centripetal force is given by

F= \frac{mv^{2}}{r}

Where v be the orbital velocity, which is given by

v=\sqrt{gr}

So, the centripetal force is given by

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So, the centripetal force

F= \frac{GMm}}{r^{2}}}

Gravitational force on the satellite having larger orbit

F= \frac{GMm}{4r^{2}} .... (1)

Gravitational force on the satellite having smaller orbit

F'= \frac{GMm}{r^{2}} .... (2)

Comparing (1) and (2),

F' = 4 F

So, the centripetal force on the satellite in the larger orbit is _one fourth_ as that on the satellite in the smaller orbit.

8 0
3 years ago
A 500 W immersion heater is placed in a pot containing 1.00 L of water at 20oC. (a) How long will the water take to rise to the
tatiyna

Answer:

96 s.

Explanation:

(a)

From the question,

Q = cm(t₂-t₁)................... Equation 1

Where Q = heat required to boil the water, c = specific heat capacity of the water, m = mass of the water, t₂ = final temperature of water, t₁ = initial temperature of water

Note: The boiling point of water = 100 °C

Given: c = 4200 J/kg.°C, t₂ = 100 °C, t₁ = 20 °C

mass of water = density×volume

m = D×v, Where D = 1000 kg/m³, v = 1.00 L = 0.001 m³

Hence, m = 1000×0.001 = 1 kg.

Substitute into equation 1

Q = 4200×1(100-20)

Q = 4200×8

Q = 33600 J.

But,

P = Q/t................... Equation 2

make t  the subject of the equation

t = Q/P................. Equation 3

Where P = power, t = time

From the question,

70 % of the available energy is absorbed by water.

P = 0.7×500 = 350 W.

Substitute into equation 2

t = 33600/350

t = 96 s.

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Megan was doing time trials on her bike around a 400m horizontal track. She took 32 seconds to travel 400m. What was her average
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To find average speed, we divide the distance of travel (in this case, 400 metres) by the time she took, 32 seconds.  Therefore: 12.5 seconds is her average speed.
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Answer:b

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Find the speed of a satellite in a circular orbit around the Earth with a radius 3.57 times the mean radius of the Earth. (Radiu
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The orbiting velocity of the satellite is 4.2km/s.

To find the answer, we need to know about the orbital velocity of a satellite.

<h3>What's the expression of orbital velocity of a satellite?</h3>
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<h3>What's the orbital velocity of a satellite orbiting earth with a radius 3.57 times the earth radius?</h3>
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=4.2km/s

Thus, we can conclude that the orbiting velocity of the satellite is 4.2km/s.

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