Question

The top of a vertical cylinder is sealed with a circular lid. If the cylinder is evacuated, what is the minimum force required to remove the lid from the top of the cylinder? The radius of the cylinder is 6.00 cm. Assume the surrounding air is at a pressure of 1 atm = 1.01 ✕ 105 Pa. Express your answer in units of newtons.

Answer 1

Answer:

F = 1142.28 N

Explanation:

It is given that,

Radius of the cylinder, r = 6 cm = 0.06 m

Pressure of the surrounding air, $P=1.01\times 10^5\ Pa$  

Let F the minimum force required to remove the lid from the top of the cylinder. We know that the force acting per unit area is called pressure exerted. Its formula is given by :

$P=\dfrac{F}{A}$

$F=P\times A$

$F=P\times \pi r^2$

$F=1.01\times 10^5\ Pa\times \pi (0.06)^2$

F = 1142.28 N

So, the minimum force required to remove the lid from the top of the cylinder is 1142.28 N. Hence, this is the required solution.