The balanced equation is Mg + 2AgNO₃ ⟶ Mg(NO₃)₂ + 2Ag
Step 1. Write the <em>unbalanced equation
</em>
Mg + AgNO₃ ⟶ Mg(NO₃)₂ + Ag
Step 2. Start with the<em> most complicated-looking formula</em> [Mg(NO₃)₂] and balance its atoms.
Mg: Already balanced —1 atom each side.
N: We need 2 N on the left. Put a 2 in front of AgNO₃.
1Mg + 2AgNO₃ ⟶ 1Mg(NO₃)₂ + Ag
O: Already balanced —6 atom6 each side.
Step 3: Balance <em>Ag</em>
We have 2Ag on the left. We need 2Ag on the right.
1Mg + 2AgNO₃ ⟶ 1Mg(NO₃)₂ + 2Ag
When ice melts, the physicals state changes from solid to liquid. The energy or the heat required (q) required to change a unit mass (m) of a substance from solid to liquid is known as the enthalpy or heat of fusion (ΔHf). The variables; q, m and ΔHf are related as:
q = m * ΔHf
the mass of ice m = 65 g
the heat of fusion of water at 0C = ΔHf = 334 J/g
Therefore: q = 65 g * 334 J/g = 21710 J
Now:
4.184 J = 1 cal
which implies that: 21710 J = 1 cal * 21710 J/4.184 J = 5188.8 cal
Hence the heat required is 5188.8 cal or 5.2 Kcal (approx)
Q = mCΔT
Q is heat in joules, m is mass, C is specific heat, and delta T is change in temp
2099 J = (40.27g)(C)(148.5 - 24.8) = .421 J / gram K
Answer:
Empirical formula of C₈H₈ = CH
Explanation:
Data Given:
Molecular Formula = C₈H₈
Empirical Formula = ?
Solution
Empirical Formula:
Empirical formula is the simplest ration of atoms in the molecule but not all numbers of atoms in a compound.
So,
tha ration of the molecular formula should be divided by whole number to get the simplest ratio of molecule
C₈H₈ Consist of Carbon (C), and Hydrogen (H)
Now
Look at the ratio of these two atoms in the compound
C : H
8 : 8
Divide the ratio by two to get simplest ratio
C : H
8/8 : 8/8
1 : 1
So for the empirical formula is the simplest ratio of carbon to hydrogen 1 : 1
So the empirical formula will be
Empirical formula of C₈H₈ = CH
Unit of M is also mole/L, where mole is the moles of solute and L is the volume of the solution. The latter is given: 158 mL or 0.158 L. So we need to find out the moles of NH4Br.
Moles of NH4Br = Mass of NH4Br/molar mass of NH4Br = 17.0g/(14+1*4+79.9)g/mol = 0.1736 mole.
So, the molarity of the solution = 0.1736mole/0.158L = 1.10 mole/L = 1.10 M
