Answer:
The equilibrium constant Kc for the reaction is :
<u>16.07 </u>
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Explanation:
The balanced equation is :
First ,
"At the equilibrium, 60% of the hydrogen gas had reacted"
This means the degree of dissociation = 60% = 0.6
Here we are denoting degree of dissociation by ="x" = 0.6
Now , consider the equation again,
H2 I2 2HI
0.35 1.6 0 (Initial Concentration)
0.35(1 - x) 1.6(1 - x) 2x (At equilibrium)
0.35(1 - 0.6) 1.6(1 - 0.6) 2(0.6)
0.14 0.64 1.2
calculate the concentration of each:
The equilibrium constant for this reaction "Kc" can be written as:
![Kc=\frac{[HI]^{2}}{[H_{2}][I_{2}]}](https://tex.z-dn.net/?f=Kc%3D%5Cfrac%7B%5BHI%5D%5E%7B2%7D%7D%7B%5BH_%7B2%7D%5D%5BI_%7B2%7D%5D%7D)
The pressure of the air is 40000N/m².
To calculate the pressure of the plane, we use the formula below.
Formula:
- P = F/A................. Equation 1
Where:
- P = Pressure of the air
- F = Force on the plane
- A = Total surface area of the plane.
From the question,
Given:
Substitute these values into equation 1
- P = 8000000/200
- P = 40000 N/m².
Hence, The pressure of the air is 40000N/m².
Learn more about pressure here: brainly.com/question/25736513
Answer:Specific heat capacity at Constant volume of Nitrogen =742.32JKg.K
Explanation:
The Specific heat capacity at Constant volume of an ideal gas is given as
c =Cv / M
Cv= Constant volue of gas
M= Molar mass
But First, we determine the Constant volume, Cv which is given as
Cv = 5/2R since Nitrogen is a diatomic gas, N2 where R= 8.314Jmol.k
= 5/2 x 8.314Jmol.K
=20.785Jmol.K
Specific heat capacity at Constant volume, c
c= Cv/M
M=molar mass = 28.0 g/mol.
changing to kg/mol =28/1000= 0.028kg/mol
Therefore c =20.785Jmol.K/0.028kg/mol
=742.32JKg.K
Answer:
Carbon monoxide is not breathable.
Explanation:
If you breath in Carbon monoxide you'll first pass out from the lack of Oxygen. If Oxygen does not reach your lungs in time death will occur from suffocation.
