34. The line shows the path of the ball.

What types of objects are using electricity in your home today?

EleoNora [17]

Lamp, tv, refrigerator, Lights, phone, microwave, surround sound, cameras, motion sensors, chandelier, pool, hot tub, heated floors, the smart home stuff, aquarium stuff, and whatever the staff uses.

3 0

3 years ago

How many grams are in 5.2 moles of Li2SO4

skelet666 [1.2K]

Answer:

572 g

Explanation:

Molar mass is the mass of 1 mol of an element or compound

molar mass of Li₂SO₄ is the sum of the products of the molar masses of the elements by the number of atoms in the compound

molar masses of each element making up lithium sulphate

Li - 7 g/mol

S - 32 g/mol

O - 16 g/mol

molar mass of Li₂SO₄ - (7 g/mol x 2) + ( 32 g/mol x 1) + ( 16 g/mol x 4 )

molar mass = 110 g/mol

mass of 1 mol of Li₂SO₄ is 110 g

therefore mass of 5.2 mol of Li₂SO₄ is - 110 g/mol x 5.2 mol = 572 g

mass is 572 g

7 0

3 years ago

The following question appears on a quiz: ""You fill a tank with gas at 60Â°C to 100 kPa and seal it. You decrease the temperatu

dusya [7]

Answer: The final pressure will decrease ad the value is 85 kPa

Explanation:

To calculate the final pressure of the system, we use the equation given by Gay-Lussac Law. This law states that pressure of the gas is directly proportional to the temperature of the gas at constant pressure.

Mathematically,

$\frac{P_1}{T_1}=\frac{P_2}{T_2}$

where,

$P_1\text{ and }T_1$ are the initial pressure and temperature of the gas.

$P_2\text{ and }T_2$ are the final pressure and temperature of the gas.

We are given:

$P_1=100kPa\\T_1=60^0C=(60+273)K=333K\\P_2=?\\T_2=10^0C=(10+273)K=283K$

Putting values in above equation, we get:

$\frac{100kPa}{333K}=\frac{P_2}{283K}\\\\P_2=85kPa$

Hence, the final pressure will decrease ad the value is 85 kPa

8 0

3 years ago

Can someone help me fill out the chart and explain what i should do, please?

Alina [70]

To determine the electronegativity for each bond you need to calculate the difference of electronegativity of the atoms forming the bond.

If the difference is equal or greater than 1.7 you have an ionic bond.

If the difference is between 0.4 and 1.6 you have a polar covalent bond.

If the difference is between 0 and less than 0.4 you have a nonpolar covalent bond.

1) In NH₃ there is a nitrogen - hydrogen bond.

electronegativity of nitrogen - electronegativity of hydrogen =

3 - 2.2 = 0.8 → polar covalent bond

2) In N₂ there is a nitrogen-nitrogen bond.

electronegativity of nitrogen - electronegativity of nitrogen =

3 - 3 = 0 → nonpolar covalent bond

3) In H₂O there is an oxygen - hydrogen bond.

electronegativity of oxygen - electronegativity of hydrogen =

3.5 - 2.2 = 1.3 → polar covalent bond

4) In PCl₃ there is a chlorine - phosphorus bond.

electronegativity of chlorine - electronegativity of phosphorus = 3 - 2.1 = 0.9 → polar covalent bond

4) In HBr there is a bromine - hydrogen bond.

electronegativity of bromine - electronegativity of hydrogen = 2.8 - 2.2 = 0.6 → polar covalent bond

5) In MgCl₂ there is a chlorine - magnesium bond.

electronegativity of chlorine - electronegativity of magnesium = 3 - 1.2 = 1.8 → ionic bond

6) In F₂ there is a fluorine - fluorine bond.

electronegativity of fluorine - electronegativity of fluorine =

4 - 4 = 0 → nonpolar covalent bond

7) In CO₂ there is an oxygen - carbon bond.

electronegativity of oxygen- electronegativity of carbon =

3.5 - 2.5 = 1 → polar covalent bond

8) In LiCl there is a chlorine - lithium bond.

electronegativity of chlorine - electronegativity of lithium =

3 - 1 = 2 → ionic bond

9) In Na₂O there is an oxygen - sodium bond.

electronegativity of oxygen - electronegativity of sodium =

3.5 - 0.9 = 2.6 → ionic bond

10) In CCl₄ there is a chlorine - carbon bond.

electronegativity of chlorine - electronegativity of carbon =

3 - 2.5 = 0.5 → polar covalent bond

5 0

3 years ago

What compound is formed when methyloxirane (1,2-epoxypropane) is reacted with ethylmagnesium bromide followed by treatment with

Pavlova-9 [17]

Answer:

Pentan-2-ol

Explanation:

On this reaction, we have a Grignard reagent (ethylmagnesium bromide), therefore we will have the production of a carbanion (step 1). Then this carbanion can attack the least substituted carbon in the epoxide in this case carbon 1 (step 2). In this step, the epoxide is open and a negative charge is generated in the oxygen. The next step, is the treatment with aqueous acid, when we add acid the hydronium ion ( $H^+$ ) would be produced, so in the reaction mechanism, we can put the hydronium ion. This ion would be attacked by the negative charge produced in the second step to produce the final molecule: "Pentan-2-ol".

See figure 1

I hope it helps!

5 0

3 years ago