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1 year ago

Open the resistance in a wire simulation, adjust only the length of the resistor, what happens to resistor?

Physics

1 answer:

Eduardwww [97]1 year ago

4 0

If we increase the length of the resistor, resistance will also increase and vice-versa.

It is given that in a wire simulation, we have to adjust only the length of the resistor.

It required to find the effect on resistor when adjust only the length of the resistor.

<h2>What happens to resistor when adjust only the length of the resistor?</h2>

As we know that the length is directly proportional to the resistance of the wire that means is we increase the size or length of the wire then it also increase the resistance present in the wire. On the other hand if we decrease the length of the wire, it will decrease the resistance. This can be represented as:

Resistance = resistivity × length/area

This is also because there is more collision of the flowing electrons in the wire to the metal ions present there.

Thus if we increase the length of the resistor, resistance will also increase and vice-versa.

Learn more about the resistance here:

brainly.com/question/11431009

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An element consists of two isotopes. The abundance of one isotope is 60.40% and its atomic mass is 68.9257 u. The atomic mass of

amm1812

Answer:

69.7173 u

Explanation:

The abundance of the first isotope is =60.40%

So the abundance of the second isotope =100%-60.40%=39.6%

Atomic mass of first isotope = 68.9257

So the average atomic mass of the first isotope =68.9257×0.6040=41.6311 u

Atomic mass of the second isotope =70.9249 u

So average atomic mass of second isotope =70.9249×0.396=28.086

Now the average atomic mass =41.6311+28.086=69.7173 u

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3 years ago

Read 2 more answers

You lift a 10-kg box to a height of 1m. How much work do you do on the box when you lift it from the ground? (g= 9.81 m/s2)

Andreyy89

Answer:

98.1 Joule

Explanation:

Solution,

⇒Mass(m)=10kg

⇒Weight(F)=Mg=10×9.81=98.1N

⇒Distance(d)=1m

Now,

Work done=F×d

=98.1×1

=98.1J

5 0

1 year ago

Hey please help Hey please help Hey please help Hey please help Hey please help

meriva

No they aren't the same

6 0

2 years ago

A solid block is attached to a spring scale. When the block is suspended in air, the scale reads 20.1 N; when it is completely i

Paha777 [63]

Answer:

A) $V = 4.92 \cdot 10^{-4} m^{3} = 492 cm^{3}$

B) $d = 4181.49 kg/m^{3} = 4.18 g/cm^{3}$

Explanation:

A) Using the Archimedes' force we can find the weight of water displaced:

$W_{d} = W_{a} - W_{w}$

Where:

$W_{a}$ : is the weight of the block in the air = 20.1 N

$W_{w}$ : is the weight of the block in the water = 15.3 N

$W_{d} = W_{a} - W_{w} = 20.1 N - 15.3 N = 4.8 N$

Now, the mass of the water displaced is:

$m = \frac{W_{d}}{g} = \frac{4.8 N}{9.81 m/s^{2}} = 0.49 kg$

The volume of the block can be found using the mass of water displaced and the density of the water:

$V = \frac{m}{d} = \frac{0.49 kg}{997 kg/m^{3}} = 4.92 \cdot 10^{-4} m^{3} = 492 cm^{3}$

B) The density of the block can be found as follows:

$d = \frac{W_{a}}{g*V} = \frac{20.1 N}{9.81 m/s^{2}*4.92 \cdot 10^{-4} m^{3}} = 4181.49 kg/m^{3} = 4.18 g/cm^{3}$

I hope it helps you!

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3 years ago

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Marizza181 [45]

Answer:

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Explanation:

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2 years ago