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bija089 [108]
1 year ago
5

Open the resistance in a wire simulation, adjust only the length of the resistor, what happens to resistor?

Physics
1 answer:
Eduardwww [97]1 year ago
4 0

If we increase the length of the resistor, resistance will also increase and vice-versa.

It is given that in a wire simulation, we have to adjust only the length of the resistor.

It required to find the effect on resistor when adjust only the length of the resistor.

<h2>What happens to resistor when adjust only the length of the resistor?</h2>

As we know that the length is directly proportional to the resistance of the wire that means is we increase the size or length of the wire then it also increase the resistance present in the wire. On the other hand if we decrease the length of the wire, it will decrease the resistance. This can be represented as:

Resistance = resistivity × length/area

This is also because there is more collision of the flowing electrons in the wire to the metal ions present there.

Thus if we increase the length of the resistor, resistance will also increase and vice-versa.

Learn more about the resistance here:

brainly.com/question/11431009

#SPJ4

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Answer:

Explanation:

She's correct but doesn't mean the wagon cannot put into motion. The force that she applied on the wagon, according to Newton's 2nd law, would have generated an acceleration, which translates into motion. The reaction force the wagon applies on her due to Newton's 3rd law, would not hinder its own motion.

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A 70.0 kg astronaut is training for accelerations that he will experience upon reentry. He is placed in a centrifuge (r = 15.0 m
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Answer:

1.3823 rad/s

20.7345 m/s

28.66129935 m/s²

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2006.29095 N radially outward

Explanation:

r = Radius = 15 m

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g = Acceleration due to gravity = 9.81 m/s²

Angular velocity is given by

\omega=13.2\times \dfrac{2\pi}{60}\\\Rightarrow \omega=1.3823\ rad/s

Angular velocity is 1.3823 rad/s

Linear velocity is given by

v=r\omega\\\Rightarrow v=15\times 1.3823\\\Rightarrow v=20.7345\ m/s

The linear velocity is 20.7345 m/s

Centripetal acceleration is given by

a_c=r\omega^2\\\Rightarrow a_c=15\times 1.3823^2\\\Rightarrow a_c=28.66129935\ m/s^2

The centripetal acceleration is 28.66129935 m/s²

Acceleration in terms of g

\dfrac{a}{g}=\dfrac{28.66129935}{9.81}\\\Rightarrow a=2.92164g

a=2.92164g

Centripetal force is given by

F_c=ma_c\\\Rightarrow F_c=70\times 28.66129935\\\Rightarrow F_c=2006.29095\ N

The centripetal force is 2006.29095 N radially outward

The torque will be experienced when the centrifuge is speeding up of slowing down i.e., when it is accelerating and decelerating.

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