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Lana71 [14]
3 years ago
14

John heats 1 kg of soup from 25 °C to 70 °C for 15 minutes by a heater. How long does the same heater take to heat 1.5 kg of the

same kind of soup from 20 °C to 80 °C? The energy output per unit time by the heater is constant.
Physics
1 answer:
Mumz [18]3 years ago
6 0

Answer:

30 minutes

Explanation:

Energy per time is constant, so:

E₁ / t₁ = E₂ / t₂

m₁C₁ΔT₁ / t₁ = m₂C₂ΔT₂ / t₂

(1 kg) C (70°C − 25°C) / 15 min = (1.5 kg) C (80°C − 20°C) / t

(1 kg) (45°C) / 15 min = (1.5 kg) (60°C) / t

3/min = 90 / t

t = 30 min

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\theta_c = \arcsin ( \frac{n_r}{n_i} ) (2)
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We can find the ratio n_r / n_i by using Snell's law:
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By using the data of the problem and re-arranging (1), we find
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